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kicyunya [14]
2 years ago
8

Indicate the FULL NAME and TOTAL NUMBER of each element in the chemical formula provided. *

Chemistry
1 answer:
REY [17]2 years ago
6 0

Answer:

4 lead  =  Pb

2 nitrogen = N

6 oxygen = O

Explanation:

Know the rules of multiplying wth perentheses.

- Hope that helped! Please let me know if you need further explanation.

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Arrange the elements in order of increasing atomic radius. Use the periodic table to help you.
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Answer:

F, S, Mg, Ba

Explanation:

Fluorine has a small atomic radius. These go up until Ba, which has a larger radius

5 0
3 years ago
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What is the volume occupied by 4.20 miles of oxygen gas (O2) at STP
Drupady [299]

Answer: 94.13 L

Explanation: In STP in an ideal gas there is a standard value for both temperature and pressure. At STP,pressure is equal to 1atm and the temperature at 0°C is equal to 273.15K. This problem is an ideal gas so we use PV=nRT where R is a constant R= 0.08205 L.atm/mol.K.

To find volume, derive the equation, it becomes V=nRT/P. Substitute the values. V= 4.20 mol( 0.08205L.atm/mol.K)(273.15K) / 1 atm = 94.13 L. The mole units, atm and K will be cancelled out and L will be the remaining unit which is for volume.

8 0
3 years ago
List the ions in solution in the electrolysis of conc.sodium chloride<br>​
Licemer1 [7]
Chloride ions Cl –(aq) (from the dissolved sodium chloride) are discharged at the positive electrode as chlorine gas, Cl 2(g) sodium ions Na +(aq) (from the dissolved sodium chloride) and hydroxide ions OH –(aq) (from the water) stay behind - they form sodium hydroxide solution, NaOH(aq)
5 0
2 years ago
The average atomic mass of a sample of an element X is 16.2u. What are the percentages of isotopes X (mass number 16, atomic num
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8 0
2 years ago
A gas occupies 1.00cm^3 at STP. What volume does it occupy at 710.0 mm Hg and 55.0°C
Lera25 [3.4K]

Answer:

Final volume is 1.29cm³

Explanation:

Using combined gas law:

P₁V₁/T₁ = P₂V₂/T₂

<em>Where P is pressure, V volume and T absolute temperature of 1, initial state and 2, final state of a gas.</em>

<em />

We can solve the volume of the gas:

P₁ = 1atm at STP

V₁ = 1cm³

T₁ = 273.15K at STP

P₂ = 710mmHg * (1atm / 760mmHg) = 0.9342atm

V₂ = ?

T₂ = 55.0°C + 273.15K = 328.15K

Replacing:

1atm*1cm³/273.15K = 0.9342atm*V₂/328.15K

1.29cm³ = V₂

<h3>Final volume is 1.29cm³</h3>

<em />

6 0
2 years ago
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