Question

Please help

Answer 1

Answer:

Range = 22.61 m

Explanation:

We can use the formula for the Range in flat ground, given by:

$Range=v_i^2\frac{sin(2\theta)}{g}$

which for our case renders:

$Range=15^2\frac{sin(80^o)}{9.8} \approx 22.61\,\,m$