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2 years ago

Please help

Physics

1 answer:

Snezhnost [94]2 years ago

4 0

Answer:

Range = 22.61 m

Explanation:

We can use the formula for the Range in flat ground, given by:

$Range=v_i^2\frac{sin(2\theta)}{g}$

which for our case renders:

$Range=15^2\frac{sin(80^o)}{9.8} \approx 22.61\,\,m$

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Answer:

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Explanation:

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Answer:

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Explanation:

Given data:

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