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kvv77 [185]
3 years ago
8

A circuit has a resistance of 8 Ohms. the voltage supplied to the circuit is 14 volts. what is the current flowing through it?

Physics
1 answer:
valina [46]3 years ago
3 0

Answer:

e jiio7ruetw5258o0pomnmitwq2690okm ,,kkkiiht44456

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- Explain how the Earth, the sun, and time are connected,
Radda [10]

Answer:

the rotation of earth is determining what part of the sun faces what part of earth making time the part thats away from the sun would be night and the one facing the sun itself would be day

6 0
2 years ago
Read 2 more answers
When are all the forces acting upon an object balanced?
Rudik [331]

Answer:

When two forces acting on an object are equal in size but act in opposite directions, we say that they are balanced forces.

Explanation:

7 0
3 years ago
A sample of helium (He) occupies 8.0 liters at 1 atm and 20.0◦C. What pressure is necessary to change the volume to 1.0 liters a
nevsk [136]

Apply the combined gas law

PV/T = const.

P = pressure, V = volume, T = temperature, PV/T must stay constant.

Initial PVT values:

P = 1atm, V = 8.0L, T = 20.0°C = 293.15K

Final PVT values:

P = ?, V = 1.0L, T = 10.0°C = 283.15K

Set the PV/T expression for the initial and final PVT values equal to each other and solve for the final P:

1(8.0)/293.15 = P(1.0)/283.15

P = 7.7atm

7 0
3 years ago
In a certain time interval, natural gas with energy content of 19000 J was piped into a house during a winter day. In the same t
Bumek [7]

Explanation:

Since, it is mentioned the there occurs no change in the temperature. This also means that there will occur no change in thermal energy of the system.

Hence, \Delta E = 0. And, as \Delta E = 0 then there will be no work involved. This means that total energy added to the house will return to the outside air as heat.

Therefore,

                   Q = -(19000 J + 2000 J)

                       = -21000 J

or,    |Q| = 21000 J

Thus, we can conclude that the magnitude of the energy transfer between the house and the outside air is 21000 J.

5 0
3 years ago
You weigh 730N. What would you weigh if the earth were six times as massive as it is and its radius were four times its present
Ber [7]

The new weight is 273.8 N

Explanation:

The weight of an object on Earth is given by

W=mg

where

m is the mass of the object

g is the acceleration of gravity

The acceleration of gravity at the Earth's surface can be rewritten as

g=\frac{GM}{R^2}

where

G is the gravitational constant

M is the Earth's mass

R is the Earth's radius

Substituting into the previous equation,

W=\frac{GMm}{R^2}

We said that in normal conditions, the weight of the person is 730 N:

W=\frac{GMm}{R^2}=730 N

Later, we are said that:

  • The mass of the Earth increases by a  factor of 6, M'=6M
  • The radius of the Earth increases by a factor of 4, R'=4R

Substituting into the equation, we find the new weight of the person in these conditions:

W'=\frac{G(6M)m}{(4R)^2}=\frac{6}{16}(\frac{GMm}{R^2})=\frac{3}{8}W

So, the new weight is 3/8 of the original weight, therefore:

W'=\frac{3}{8}(730)=273.8 N

Learn more about gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

3 0
3 years ago
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