A circuit has a resistance of 8 Ohms. the voltage supplied to the circuit is 14 volts. what is the current flowing through it?

An alarm clock is dropped off the edge of a tall building. You, standing directly under it, hear a tone of 1350 Hz coming from t

frozen [14]

Answer:

the frequency clock would be 1262.85 Hz

Explanation:

Given data;

height of building h = 25 m

from the third equation of motion;

v² = u² + 2as

Since the Alarm clock falls with an acceleration equal to the acceleration due to gravity; a = g = 9.81 m/s²

initial velocity u = 0

so we substitute our values into the kinematic equation

v² = (0)² + 2 × 9.81 × 25

v² = 490.5

v = √490.5

v = 22.1472 m/s

Now, since the alarm clock is moving both I am stationary;

my velocity will be zero.

so Frequency of the alarm clock will be;

f' = [ (v - $v_{s}$ ) / ( v + $v_{0}$ ) ] × f

we know that; speed of sound is 343 m/s, so v = 343 m/s, $v_{s}$ is 22.1472 m/s, f is 1350 Hz, $v_{0}$ is 0 m/s

so we substitute the values into the equation

f' = [ (343 - 22.142 ) / ( 343 + 0 ) ] × 1350

f' = [ 320.858 / 343 ] × 1350

f' = 0.935446 × 1350

f' = 1262.85 Hz

Therefore, the frequency clock would be 1262.85 Hz

6 0

2 years ago

My experience as a learner

Artist 52 [7]

So I'm guessing that the question is describing your experiences in both these classes? Nobody else knows how you experienced these classes because it was your experience, not mine or anyone else's. You'll have to explain how you felt about the class, and whether it was difficult or not, etc.

8 0

3 years ago

Which if these events happens first in earths polar regions

LiRa [457]

Where are the answer choices

8 0

3 years ago

What is the difference between work done by the gravitational force on descending and ascending objects?

Kazeer [188]

<span>The difference between work done by the gravitational force on descending and ascending objects is that for descending objects a terminal velocity will be reached where the object will not fall any faster that it already is. For an ascending object, its velocity will come down the longer gravity has an effect on it until the object begins to descend and the velocity of an ascending object will continue to change the longer gravity has an effect on it.</span>

8 0

3 years ago

A motorcycle begins at rest and accelerates uniformly S7.9 we want to find a time to take the motorcycle to reach a speed of 100

Len [333]

The motorbike reaches 100 km/h in 3.5 seconds

Explanation:

The motion of the motorbike is a uniformly accelerated motion (= constant acceleration), therefore we can use the following suvat equation:

$v=u+at$