Answer: Use the formula q = m·ΔHv in which q = heat energy, m = mass, and ΔHv = heat of vaporization.
Answer:
not captured for use by living things
Explanation:
The sun is a star with a high radiation and most of(around 55-67%) the radiation that reaches the earth is usually reflected back. The earth cannot use all the energy that reaches the earth. It uses almost around 15-30%
Answer:
The current in the second loop will stay constant
Explanation:
Since the induced emf in the second coil, ε due to the changing current i₁ in the first wire loop ε = -Mdi₁/dt where M = mutual inductance of the coils and di₁/dt = rate of change of current in the first coil = + 1 A/s (positive since it is clockwise)
Now ε = i₂R where i₂ = current in second wire loop and R = resistance of second wire loop.
So, i₂R = -Mdi₁/dt
i₂ = -Mdi₁/dt/R
Since di₁/dt = + 1 A/s,
i₂ = -Mdi₁/dt/R
i₂ = -M × + 1 A/s/R
i₂ = -M/R
Since M and R are constant, this implies that i₂ = constant
<u>So, the current in the second wire loop will stay constant.</u>
Answer:
1.6 m/s2
Explanation:
Let 
be the gravitational acceleration of the moon. We know that due to the law of energy conservation, kinetic energy (and speed) of the rock when being thrown upwards from the surface and when it returns to the surface is the same. Given that stays constant, we can conclude that the time it takes to reach its highest point, aka 0 velocity, is the same as the time it takes to fall down from that point to the surface, which is half of the total time, or 4 / 2 = 2 seconds.
So essentially it takes 2s to decelerate from 3.2 m/s to 0. We can use this information to calculate
So the gravitational acceleration on the Moon is 1.6 m/s2
