(a)
KE = m v^2 / 2 = (1200 kg)(20 m/s)^2 / 2 = 240,000 J
(b)
The energy is entirely dissipated by the force of friction in the brake system.
(c)
W = delta KE = KEf - KEi = (0 - 240,000) J = -240,000 J
(d)
Fd = delta KE
F = (delta KE) / d = (-240,000 J) / (50 m) = -4800 N
The magnitude of the friction force is 4800 N.
Because your brain cant handle all of the information.
Answer:
0.203 micro meter
Explanation:
for destructive interference that appearsblack, use the formula
2 t = m λ / u (where m = 0 1 2 3 ... is order of minima)
where t = tickness,
u is the ref index = 1.32
Wavelenth λ = 535×10^-9 meter
for t (minimum) m = 1 (as m=0 is ruled out as t>0)
t = 1× 535×10^-9/2×1.32
t (min) = 202.65×10^-9 meter
OR
t (min) = 0.203×10^-6 meter = 0.203 micro meter
If a battery with a potential difference of 1.5 volts is placed across the plates, the maximum capacitor will have a charge of 36 V.
<h3>What possible variations are there in a 1.5 volt battery?</h3>
1 V is, by definition, a potential energy differential between two places equal to one joule for every coulomb of charge. Your query is resolved by that. Between the sites where that potential difference is measured, 1.5V denotes a potential energy differential of 1.5 joules per coulomb.
<h3>How do you determine the difference in potential energy?</h3>
ΔV=VB−VA=ΔPEq. By dividing the potential energy of a charge q that has been transported from point A to point B by the charge, we may define the potential difference between points A and B as VBVA. The joules per coulomb, sometimes known as volts (V) in honor of Alessandro Volta, are the units of potential difference.
To know more about potential energy difference visit ;
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Answer:
The value of the magnetic field is 
Explanation:
From the question we are told that
The number of turns is 
The area of the loop is 
The angle is 
The torque is 
The current is 
The torque acting on the current carry loop is mathematically represented as
Where is the magnitude of the magnetic filed
Making B the subject
Substituting values
