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Stells [14]
3 years ago
9

Just like energy is matter is lost through an ecosystem

Physics
2 answers:
Novosadov [1.4K]3 years ago
7 0
Yes energy is reduced 
Bumek [7]3 years ago
6 0
I think its false. because sublimation occurs when water changes into water vapor. i hope this helps.
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How can the IMA of a first- class lever be increased?
Dimas [21]
IMA = Ideal Mechanical Advantage

First class lever = > F1 * x2 = F2 * x1

Where F1 is the force applied to beat F2. The distance from F1 and the pivot is x1 and the distance from F2 and the pivot is x2

=> F1/F2 = x1 /x2

IMA = F1/F2 = x1/x2

Now you can see the effects of changing F1, F2, x1 and x2.

If you decrease the lengt X1 between the applied effort (F1) and the pivot,  IMA decreases.

If you increase the length X1 between the applied effort (F1) and the pivot, IMA increases.

If you decrease the applied effort (F1) and increase the distance between it and the pivot (X1) the new IMA may incrase or decrase depending on the ratio of the changes.

If you decrease the applied effort (F1) and decrease the distance between it and the pivot  (X1) IMA will decrease.

Answer: Increase the length between the applied effort and the pivot.
4 0
3 years ago
Read 2 more answers
When a certain string is clamped at both ends, the lowest four resonant frequencies are 50, 100, 150, and 200 Hz. When the strin
mario62 [17]

Answer:

Explanation:

Given

Lowest four resonance frequencies are given with magnitude

50,100,150 and 200 Hz

The frequency of vibrating string is given by

f=\frac{n}{2L}\sqrt{\frac{T}{\mu }}

where n=1,2,3 or ...n

L=Length of string

T=Tension

\mu =Mass per unit length

When string is clamped at mid-point

Effecting length becomes L'=0.5 L

Thus new Frequency becomes

f' =\frac{n}{L}\sqrt{\frac{T}{\mu }}

i.e. New frequency is double of old

so new lowest four resonant frequencies are 100,200,300 and 400 Hz      

4 0
3 years ago
Proses mendidihnya air.jelaskan!
inn [45]
air akan mendidih pada suhu 100 derajat celcius.air akan selalu pada suhu tersebut,jika lebih dari itu air akan menguap
7 0
3 years ago
A person travels by car from one city to another with differem constan1 speeds between pairs of cities. She drives for 30.0 min
Montano1993 [528]

Answer:

a.52.9 km/h

b.90 km

Explanation:

We are given that

v_1=89km/h

t_1=30min

v_2=100km/h

t_2=12min

v_3=40km/h

t_3=45 min

Time spend on eating lunch and buying ga=15 min.

a.Total time=30+12+45+15=102 minute=\frac{102}{60}=1.7 hour

1 hour=60 minutes

Distance=speed\times time

d_1=v_1\times t_1=80\times\frac{30}{60}=40km

d_2=100\times \frac{12}{60}=20 km

d_3=40\times \frac{45}{60}=30 km

Total distance=d_1+d_2+d_3=40+20+30=90km

Average speed=\frac{total\;speed}{total\;time}

Using the formula

Average speed=\frac{90}{1.7}=52.9Km/h

b.Total distance between the initial and final city lies along the route=90 km

4 0
3 years ago
A 200 N trash can is pulled across the sidewalk by a person at constant speed by a force of 75 N. What is the coefficient of fri
Pavel [41]

Answer:

μ = 0.375

Explanation:

F = Applied force on the trash can = 75 N

W = weight of the trash can = 200 N

f = frictional force acting on trash can

Since the trash can moves at constant speed, force equation for the motion of can is given as

F - f = 0

75 - f = 0

f = 75 N

μ = Coefficient of friction

frictional force is given as

f = μ W

75 = μ (200)

μ = 0.375

5 0
3 years ago
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