<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %
<u>Explanation:</u>
The given chemical formula of lead (IV) carbonate is 
To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:
Mass of lead = (1 × 207.2) = 207.2 g
Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g
Putting values in above equation, we get:
Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %
Main Answer:
Given
pH = -log[H+]
= -log[0.00017]
= 3.769
We know that
pW = pH + pOH
and pW =14
pOH = 14-pH
=14-3.769
=10.231
According to the definition
pOH = -log[OH-]
10.231 = log[OH-]-1
[OH-]= 5.87 x 10-11
Explanation:
What is pH?
pH is defined as the concentration of H+ ion in the solution. If the pH value is less than 7, then the solution will be acidic. If the pH value is greater than 7, then the solution will be basic.
To know more about pH, please visit:
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The answer its O-H.........
