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2 years ago

Help please 1 thought 3

Mathematics

1 answer:

Anastaziya [24]2 years ago

6 0

A function is a relation that has one output for a given input.

For the first one, there is no one x value with two or more y values so it is a function.

The second example is also a function because a certain value can only have one cube root.

For problem number 3 input "-3" for every instance of x in h(x).

So, h(-3)=2(3^2)-1= 17

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The first term of a geometric sequence

nadezda [96]

Answer:

Step-by-step explanation:

a₆ = a₁r⁶⁻¹ = (-2)4⁵ = -2048

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1 year ago

Can you please answer this question

tamaranim1 [39]

$3tan^{2} \theta +7sec\theta=3$
First I converted the equation terms into sine and cosine.
$tan^{2}\theta = \frac{sin^{2}\theta}{cos^{2}\theta}$ and $sec\theta= \frac{1}{cos\theta}$
Substitution:
$\frac{3sin^2\theta}{cos^2\theta} + \frac{7}{cos\theta} =3$
Common Denominator Created:
$\frac{3sin^2\theta}{cos^2\theta} + \frac{7cos\theta}{cos^2\theta} =3$
Multiply each term by the LCD:
$3sin^2\theta+7cos\theta=3cos^2\theta$
Substitution: Recall ⇒ $sin^2\theta =1-cos^2\theta$
$3(1-cos^2\theta)+7cos\theta=3cos^2\theta$
Distribute and collect all terms on one side:
$6cos^2\theta-7cos\theta-3=0$
Factor and set each factor equal to 0:
$(2cos\theta-3)(3cos\theta+1)=0$
$2cos\theta-3=0$ ⇒ $theta=cos^{-1} \frac{3}{2}$
$3cos\theta+1=0$ ⇒ $theta=cos^{-1} \frac{-1}{3}$
The 2nd factor provides only possible answer 109.5 degrees

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2 years ago

If f(x)=x2+2x+3 what is the value of f(x) when x=6

Marat540 [252]

The answer is 51

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3 years ago

Mr. Smith ate a snack with 80.79 total calories. If the chips he ate were 43.39 calories, how

Paul [167]

Answer:

37.40 calories

Hope this helps :)

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2 years ago

How do you solve secx-2=0

siniylev [52]

It will be secx = 2
or, cosx = 1/2
or x = Π/3 , 5Π/3

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2 years ago

Help please 1 thought 3​

Help please 1 thought 3