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Anna [14]
3 years ago
6

Please help with this chemistry question above!

Chemistry
1 answer:
Lady_Fox [76]3 years ago
3 0

Hey there!

Your answer is B. CO₂.

This molecule consists of two polar bonds, but they cancel each other out because they are pointing away from each other.

Because the forces of the bonds cancel out, the molecule itself is nonpolar.

Hope this helps!

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An 80.0-gram sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its
german
Hello!

First you need to calculate q 
<span>delta U is change in internal energy </span>

<span>delta U = q + w </span>
<span>q is heat and w work done </span>
<span>here work was done by the system means energy leaving the system so w is negative </span>

<span>delta U = q + w </span>

<span>q = delta U - w = 6865 J - (-346 J) = 7211 J = 7.211 KJ </span>

<span>q = m x c x delta T </span>

<span>7211 J = 80.0 g x c x (225-25) °C </span>

<span>c = 0.451 J /g °C
</span>
Hope this Helps! Have A Wonderful Day! :)
5 0
3 years ago
I made a cup of coffee on the stove and when I went to check on it four hours later, there was no more water in the kettle.
11Alexandr11 [23.1K]
No the water evaporated 
i think :) :) 

3 0
3 years ago
Read 2 more answers
Please help! (no links)
Rus_ich [418]
It's D because I know bcz I'm smart 8 times 8 is 60-nart
5 0
3 years ago
What is the velosity of a 72.3 kg jogger with a kinetic energy of 1080.0 J?
Svet_ta [14]

Answer: 5.47m/s

Explanation:

Mass = 72.3kg

K.E = 1080.0J

V =?

K.E = 1 /2MV^2

V^2 = 2K.E /M = (2x1080)/72.3

V = sqrt [(2x1080)/72.3]

V = 5.47m/s

7 0
3 years ago
Question 3) A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of
Masja [62]

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

<u>Explanation:</u>

We have the chemical equation,

HF (aq)+NaOH(aq)->NaF(aq)+H2O

To find how many moles have been used in this

c= n/V=> n= c.V

nHF=0.250 M⋅1.5 L=0.375 moles HF

Simillarly

nF=0.250 M⋅1.5 L=0.375 moles F

nHF=0.375 moles - 0.250 moles=0.125 moles

nF=0.375 moles+0.250 moles=0.625 moles

[HF]=0.125 moles/1.5 L=0.0834 M

[F−]=0.625 moles/1.5 L=0.4167 M

To determine the problem using the Henderson - Hasselbalch equation

pH=pKa+log ([conjugate base/[weak acid])

Find the value of Ka

pKa=−log(Ka)

pH=−log(Ka) +log([F−]/[HF]

pH= -log(3.5 x 10 ^4)+log(0.4167 M/0.0834 M)

pH=-log(3.5 x 10 ^4)+log(4.996)

pH= -4.54+0.698

pH=-(-3.84)

pH=3.84

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

5 0
3 years ago
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