Answer:
V = 6.17 L
Explanation:
Given data:
Volume = ?
Number of moles = 0.382 mol
Pressure = 1.50 atm
Temperature = 295 k
R = 0.0821 L. atm. /mol. k
Solution:
According to ideal gas equation:
PV= nRT
V = nRT/P
V = 0.382 mol × 0.0821 L. atm. /mol. k ×295 k / 1.50 atm
V = 9.252 L. atm. / 1.50 atm
V = 6.17 L
Cl2 is nonpolar so it has to be only London dispersion force (LDF)
Answer:
Some of the properties of cobalt silicate include:
It occurs as a crystal with red- violet type colour.
The shape of the cobalt silicate crystal is orthorhombic.
The molecular weight of cobalt silicate is 209.95.
The melting temperature of Cobalt Silicate is 1618 degrees Celsius.
The density of Cobalt Silicate is 4.63 grams per centimetre cube.
Cobalt Silicate can serve as a semi-conductor.
