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3 years ago

Plz Help me with this ?

Chemistry

2 answers:

11Alexandr11 [23.1K]3 years ago

6 0

<h3>Answer: This is a convergent boundary. Here, a oceanic crust collides with a continental crust </h3><h3 /><h3><3 have a nice day </h3>

Arte-miy333 [17]3 years ago

5 0

Answer:

Hey there!

This is a convergent boundary. Here, a oceanic crust collides with a continental crust.

Hope this helps :)

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Be sure to answer all parts. Write the balanced equations corresponding to the following rate expressions: a) rate = − 1 3 Δ[CH4

Alinara [238K]

Answer : The balanced equations will be:

(a) $3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH$

(b) $2N_2O_5\rightarrow 2N_2+5O_2$

(c) $2H_2+2CO_2+O_2\rightarrow 2H_2CO_3$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

Now we have to determine the balanced equations corresponding to the following rate expressions.

(a) $Rate=-\frac{1}{3}\frac{d[CH_4]}{dt}=-\frac{1}{2}\frac{d[H_2O]}{dt}=-\frac{d[CO_2]}{dt}=+\frac{1}{4}\frac{d[CH_3OH]}{dt}$

The balanced equations will be:

$3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH$

(b) $Rate=-\frac{1}{2}\frac{d[N_2O_5]}{dt}=+\frac{1}{2}\frac{d[N_2]}{dt}=+\frac{1}{5}\frac{d[O_2]}{dt}$

The balanced equations will be:

$2N_2O_5\rightarrow 2N_2+5O_2$

(c) $Rate=-\frac{1}{2}\frac{d[H_2]}{dt}=-\frac{1}{2}\frac{d[CO_2]}{dt}=-\frac{d[O_2]}{dt}=+\frac{1}{2}\frac{d[H_2CO_3]}{dt}$

The balanced equations will be:

$2H_2+2CO_2+O_2\rightarrow 2H_2CO_3$

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3 years ago

A chemist is likely to do which of the following? . . 1)write a formula for a paint coating . 2)explore land areas for digging o

Serggg [28]

"W<span>rite a formula for a paint coating" is the one among the following choices given in the question that a chemist is likely to do. The correct option among all the options that are given in the question is the first option or option "1". I hope that this answer has actually come to your help.</span>

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3 years ago

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Why are there two chlorine atoms for every magnesium atom in the compound NaCl2?

BlackZzzverrR [31]

Answer : Note : The formula give in the question needs to be corrected , the formula of two chlorine atoms for every magnesium atom in the compound is $MgCl_{2}$ which is Magnesium Chloride.

Explanation : To write the formula of the compound we need to know the charge of the atoms or elements involved in the formula.

Charge of Mg is +2 and charge of Cl is -1 , to write the formula of the compound we always criss cross the charges. And also when we write the formula the total (or net) charge of the compound should be 0. Charge of Mg is +2 so to get the total(net) charge as 0 we need two Cl atoms with each -1 charge.

Mg = +2 , Cl = -1 , Cl = -1

2 Cl = -1 + (-1) = -2

Mg = +2 and 2 Cl = -2

+2 -2 = 0

$MgCl_{2}\rightarrow Mg^{+2} + 2Cl^{-}$

So the formula for Magnesium Chloride is $MgCl_{2}$

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Rick has taken a loan of $3,200 from the bank to buy new appliances. His first loan payment is due at the end of this month. He

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Answer:

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