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Tresset [83]
3 years ago
7

a gas is contained in a thick walled balloon. when the pressure changes from 417 mm hg to 576 mm hg, the volume changes from l t

o 4.78 l and the temperature changes from 497 k to 386k
Chemistry
1 answer:
melomori [17]3 years ago
7 0
We can use the combined gas law equation to solve for the initial volume
\frac{P1V1}{T1} =  \frac{P2V2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting the values in the equation 
\frac{417 mmHg*V}{497 K} =  \frac{576mmHg*4.78L}{386K}
V = 8.50 L
the initial volume is 8.50 L
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