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3 years ago

Which of the following is known as the use of a wave?

Physics

1 answer:

TiliK225 [7]3 years ago

7 0

Answer:

Explanation:

Waves involve the transport of energy without the transport of matter. In conclusion, a wave can be described as a disturbance that travels through a medium, transporting energy from one location (its source) to another location without transporting matter.

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NO LINKS!!!!!! Help its urgent, PLEASE HELP!!!!!!!!!!!!!!!!

Likurg_2 [28]

Answer:

I think ur answer would be B

Explanation:

srry if wrong

hope this helps

7 0

3 years ago

The index of refraction of a clear plastic is listed as 1.89 in the book, but you measured the angle of incidence 63.5° and the

lakkis [162]

Answer:

<h2>index of refraction = 1.69</h2><h2>percentage error = 10.58%</h2>

Explanation:

According to Snell's law, the ratio of the sine of angle of incidence to the sine of angle of refraction is a constant for a given pair of media. The constant is known as the refractive index.

Mathematically $\frac{sin i}{sin r} = n$

i = angle of incidence measured = 63.5°

r = angle of refraction measured = 32°

n = refractive index

$n = \frac{sin 63.5^{0} }{sin 32^{0} } \\n = \frac{0.8949}{0.5299}\\ n = 1.69$

The index fraction calculated is approx. 1.69.

If the index of refraction of a clear plastic as listed in the book is 1.89 and the calculated is 1.69, the percentage error will be calculated as thus;

%error = $\frac{1.89-1.69}{1.89} * 100$

%error = $\frac{0.2}{1.89}*100$

%error = $\frac{20}{1.89}$

%error = 10.58%

6 0

3 years ago

An ice skater of mass m = 60 kg coasts at a speed of v = 0.8 m/s past a pole. At the distance of closest approach, her center of

IrinaVladis [17]

Answer:

1.78 rad/s

1.70344 rad/s

Explanation:

v = Velocity = 0.8 m/s

m = Mass of person = 60 kg

$r_1$ = Distance between center of mass of person and pole = 0.45 m

$r_2$ = New distance between center of mass of person and pole = 0.46 m

I = Moment of inertia

Angular speed is given by

$\omega_1=\dfrac{v}{r_1}\\\Rightarrow \omega_1=\dfrac{0.8}{0.45}\\\Rightarrow \omega_1=1.78\ rad/s$

The angular speed is 1.78 rad/s

In this system the angular momentum is conserved

$L_1=L_2\\\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow mr_1^2\omega_1=mr_2^2\omega_2\\\Rightarrow \omega_2=\dfrac{r_1^2\omega_1}{r_2^2}\\\Rightarrow \omega_2=\dfrac{0.45^2\times 1.78}{0.46^2}\\\Rightarrow \omega_2=1.70344\ rad/s$