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sertanlavr [38]
2 years ago
15

Can you answer the b. thanks

Physics
1 answer:
levacccp [35]2 years ago
4 0

Answer:

current going into a junction in a circuit is EQUAL TO the current comming out of the junction.

Explanation:

Krichhoff's Current Law

Kirchhoff's current law (1st Law) states that current flowing into a node (or a junction) must be equal to current flowing out of it.

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The heart working with the blood vessels to pump blood is which body system?
LiRa [457]
I think it’s the cardiovascular system
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Do not have definite size and always take the shape of their container,
vekshin1
Liquids is the answer
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C'est quoi le lien entre l'atmosphere et les plantes?
Rus_ich [418]

Answer:

Les plantes produisent de l'oxygène et ont contribué à faire de la Terre une planète habitable. Grâce au processus de photosynthèse pendant la journée, les plantes absorbent le dioxyde de carbone de l'air, le convertissent en sucre et libèrent de l'oxygène dans l'atmosphère.

Les plantes consomment du dioxyde de carbone - un gaz à effet de serre important - au cours du processus de photosynthèse. La réduction du dioxyde de carbone dans l'atmosphère a un effet de refroidissement indirect. Les plantes refroidissent également l'atmosphère car elles libèrent de la vapeur d'eau lorsqu'elles deviennent chaudes, un processus similaire à la transpiration.

la température, l'humidité et l'intensité lumineuse autour de la plante; la concentration de dioxyde de carbone dans l'air autour des feuilles. La relation est inverse; autrement dit, à mesure que la concentration de CO2 augmente, le nombre de stomates produits diminue, et vice versa.

Explanation:

3 0
2 years ago
A person hears a siren as a fire truck approaches and passes by. The frequency varies from 480Hz on approach to 400Hz going away
alekssr [168]

Answer:

31.2 m/s

Explanation:

f_{app} = Frequency of approach = 480 Hz

f_{aw} = Frequency of going away = 400 Hz

V = Speed of sound in air = 343 m/s

v = Speed of truck

Frequency of approach is given as

f_{app} = \frac{Vf}{V - v}                           eq-1

Frequency of moving awayy is given as

f_{aw} = \frac{Vf}{V + v}                          eq-2

Dividing eq-1 by eq-2

\frac{f_{app}}{f_{aw}} = \frac{V + v}{V - v}

\frac{480}{400} = \frac{343 + v}{343 - v}

v = 31.2 m/s

7 0
3 years ago
A soccer ball with mass 0.450 kg is initially moving with speed 2.20 m/s. A soccer player kicks the ball, exerting a constant fo
Alinara [238K]

Answer:

0.187 m

Explanation:

We'll begin by calculating the acceleration of the ball. This can be obtained as follow:

Mass (m) = 0.450 Kg

Force (F) = 38 N

Acceleration (a) =?

F = m × a

38 = 0.450 × a

Divide both side by 0.450

a = 38 / 0.450

a = 84.44 m/s²

Finally, we shall determine the distance. This can be obtained as follow:

Initial velocity (u) = 2.20 m/s.

Final velocity (v) = 6 m/s

Acceleration (a) = 84.44 m/s²

Distance (s) =?

v² = u² + 2as

6² = 2.2² + (2 × 84.44 × s)

36 = 4.4 + 168.88s

Collect like terms

36 – 4.84 = 168.88s

31.52 = 168.88s

Divide both side by 168.88

s = 31.52 / 168.88

s = 0.187 m

Thus, the distance is 0.187 m

6 0
3 years ago
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