Which of these common substances is a homogeneous mixture?
2 answers:
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Explanation:
Chemical reaction equation for the give decomposition of is as follows:.
And, initially only is present.
The given data is as follows.
= 2.3 atm at equilibrium
= 0.69 atm
Therefore,
= 0.23 aatm
So, = 2.3 - 2(0.23)
= 1.84 atm
Now, expression for will be as follows.
=
= 0.0224
or,
Thus, we can conclude that the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is .
Answer:
The answer to your question is: kc = 6.48
Explanation:
Data
Given Molecular weight
CaO = 44.6 g 56 g
CO₂ = 26 g 44 g
CaCO₃ = 42.3 g 100 g
Find moles
CaO 56 g ---------------- 1 mol
44.6 g -------------- x
x = (44.6 x 1) / 56 = 0.8 mol
CO₂ 44 g ----------------- 1 mol
26 g ---------------- x
x = (26 x 1 ) / 44 = 0.6 moles
CaCO₃ 100 g --------------- 1 mol
42.3g -------------- x
x = (42.3 x 1) / 100 = 0.423 moles
Concentrations
CaO = 0.8 / 6.5 = 0.12 M
CO₂ = 0.6 / 6.5 = 0.09 M
CaCO₃ = 0.423 / 6.5 = 0.07 M
Equilibrium constant =
Kc = [0.07] / [[0.12][0.09]
Kc = 0.07 / 0.0108
kc = 6.48