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Anika [276]
3 years ago
10

Choose a likely identity for X, Y, and Z in these structures. A central X atom is bonded to two chlorine atoms through single bo

nds. There are three lone pairs of electrons on each chlorine atom. C O B Be F N A central Y atom is bonded to three chlorine atoms through single bonds. There are three lone pairs of electrons on each chlorine atom. A central Z atom is bonded to two chlorine atoms through single bonds. There are three lone pairs of electrons on each chlorine atom and two lone pairs of electrons on the Z atom. C O N F Be B F C N Be B O

Chemistry
1 answer:
natka813 [3]3 years ago
6 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

X  is Be

Y  is B

Z  is  O            

Explanation:

In order to understand the solution, we need to that the an element form a bond based on

1  The number of valence electron available in its atom

2 The  number of electron it require to attains its stable state i.e its Octet  state

        The number of valence electron for each of the option  are

                 F = 7,   N = 5 , O = 6 , C = 4 , B = 3 , Be = 2

 Considering the first element

           We see that  X is donating  two valence electron in its atom and it is donating it to 2  Cl as Cl  only requires a single electron to achieve its stable state

Now looking  option we can see that  Be has two valence  electron in it atom and in order for it to attain its stable state it needs to release the electron so the correct option for this question is Be

Considering the second  element              

      We see that  Y is donating  three valence electron in its atom and it is donating it to 3  Cl as Cl  only requires a single electron to achieve its stable state    

    Now looking  option we can see that  B has three valence  electron in it atom and in order for it to attain its stable state it needs to release the valence electron so the correct option for this question is B

Considering the second  element  

      We see that  Z is donating two valence electron in its atom and it is donating it to 2  Cl as Cl  only requires a single electron to achieve its stable state, also Z has 2 lone-pair valence electron

       Now looking at the option we can see that  O has 6 valence electron so if it donates 2 valence electron it will still be left with 4 - pair of electron

   Therefore the correct option to this question is  O                  

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nadya68 [22]

Answer:

Explanation:

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Number of moles = mass / molar mass

Number of moles = 40.1 g/ 40.1 g/mol

Number of moles = 1 mol

b = 11.5 g Na

Number of moles = mass / molar mass

Number of moles = 11.5 g/ 23 g/mol

Number of moles = 0.5 mol

c = 5.87 g Ni

Number of moles = mass / molar mass

Number of moles = 5.87 g/ 58.7 g/mol

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d = 150 g of S

Number of moles = mass / molar mass

Number of moles = 150 g/ 32 g/mol

Number of moles = 4.7 mol

e = 2.65 g Fe

Number of moles = mass / molar mass

Number of moles = 2.65 g/ 55.85 g/mol

Number of moles = 0.05 mol

f = 0.00750 g Ag

Number of moles = mass / molar mass

Number of moles = 0.00750 g/ 107.9 g/mol

Number of moles = 6.95 × 10⁻⁵ mol

g = 2.25 × 10²⁵ atoms Zn

1 mole = 6.022 × 10²³ atoms

1 mol / 6.022 × 10²³ atoms × 2.25 × 10²⁵ atoms

0.17  × 2.25 × 10²⁵ moles

38.25 moles

h = 50 atoms of Ba

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6 0
3 years ago
Natural gas is a mixture of many substances, primarily CH₄, C₂H₆, C3H8, and C4₄H₁₀. assuming that the total pressure of the gase
olchik [2.2K]

Answer:

A. The partial pressure for CH4 = 0.0925atm

B. The partial pressure for C2H6 = 0.925atm

C. The partial pressure for C3H8 = 0.346atm

D. The partial pressure for C4H10 = 0.115atm

Explanation:

Total pressure = 1.48atm

Total mole = 0.4+4+1.5+0.5=6.4

A. Mole fraction of CH4 = 0.4/6.4 = 0.0625

The partial pressure for CH4 = 0.0625 x 1.48 = 0.0925atm

B. Mole fraction of C2H6 = 4/6.4 = 0.625

The partial pressure for C2H6 = 0.625 x 1.48 = 0.925atm

C. Mole fraction of C3H8 = 1.5/6.4 = 0.234

The partial pressure for C3H8 = 0.234 x 1.48 = 0.346atm

D. Mole fraction of C4H10 = 0.5/6.4 = 0.078

The partial pressure for C4H10 = 0.078 x 1.48 = 0.115atm

7 0
3 years ago
Determine how many liters of hydrogen adjusted to STP there are in a 50.0 liter steel cylinder if the pressure inside is 100.0 a
Dvinal [7]

Answer : The volume of hydrogen gas at STP is 4550 L.

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 100.0 atm

P_2 = final pressure of gas at STP = 1 atm

V_1 = initial volume of gas = 50.0 L

V_2 = final volume of gas at STP = ?

T_1 = initial temperature of gas = 27.0^oC=273+27.0=300K

T_2 = final temperature of gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{100.0atm\times 50.0L}{300K}=\frac{1atm\times V_2}{273K}

V_2=4550L

Therefore, the volume of hydrogen gas at STP is 4550 L.

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2 years ago
Fill in the blanks below.
Elenna [48]

Answer:

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2. In the equation, CO₂ is a___reactant_____.

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6. The number of oxygen atoms on the left side of the equation is__equal to_________ the number of oxygen atoms on the right side.

5 0
3 years ago
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