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Gnesinka [82]
3 years ago
7

An airplane flies 2500 miles east in 245 seconds what is the velocity of the plane?

Physics
1 answer:
forsale [732]3 years ago
8 0

Speed = (distance) / (time)

Speed = (

Velocity = speed, and its direction

The velocity of the plane is 10.2 miles per second East.

(about 48 times the speed of sound)

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How do we get this equation ??<br><br><br> H=V^2÷R
lesantik [10]

H=\frac{V^2}{R}\times t is the equation that represents the Joule's law of heating.

<h3>Explanation:</h3>

Joule's law of heating defines the heat generated by any current flowing conductor is directly proportional to  

1. Square of Current (I²),

2. Resistance of the conductor (R)

3. Time for which current is passed (t)

Hence, Heat generated = H = I^2 Rt .....................(1)

By Ohm's Law, the potential difference (V) across a conductor is directly proportional to the current(I) flowing through it. The constant of proportionality is termed as resistance of the conductor (R).

V\ \alpha\ I\\V=I\times R ...............................................(2)

From (2), Current (I) can be rewritten as

I = \frac{V}{R} ........................................................(3)

Substituting (3) in (1), we get

H = I^2\times R\times t \\=(\frac{V}{R} )^2\times R\times t\\\\=\frac{V^2}{R^2}\times R\times t = \frac{V^2}{R}\times t\\\\ H =\frac{V^2}{R}\times t

3 0
3 years ago
An eagle is flying horizontally at a speed of 2.60 m/s when the fish in her talons wiggles loose and falls into the lake 4.60 m
sergij07 [2.7K]

Answer:

9.495 m/s

Explanation:

initial horizontal speed, ux = 2.60 m/s

initial vertical speed, uy = 0

height, h = 4.60 m

acceleration due to gravity, g = 9.8 m/s^2

Let the speed of fish is v as it hits the water level.

Use third equation of motion in vertical direction

v^{2}= u^{2}+2as

v^{2}= 0^{2}+2\times 9.8\times 4.60

v = 9.495 m/s

Thus, the fish hits the water level with the speed of 9.495 m/s.

8 0
3 years ago
27. The pressure at A is 9.5 atm and the water velocity is 10 m/s. What is the water velocity at point C
pogonyaev

Answer:

10 m/s

Explanation:

6 0
3 years ago
Some enterprising physics students working on a catapult decide to have a water balloon fight in the school hallway. the ceiling
ivanzaharov [21]
Given:
v = 11 m/s, the launch speed
h = 3.6 m, the height of the ceiling

Assume g = 9.8 m/s², and neglect air resistance.
Let θ =  the launch angle, measured above the horizontal.
The initial vertical speed is
u = 11 sin θ m/s 

At the maximum height of 3.6 m, the vertical velocity is zero.
Therefore
(11 sinθ m/s)² - 2*(9.8 m/s²)*(3.6 m) = 0
121 sin² θ = 70.56
sin²θ = 0.5831
sin θ = 0.7636
θ = sin⁻¹ 0.7636 = 49.8° ≈ 50°

Answer: 50° above the horizontal
8 0
3 years ago
Number 38 please!!!
vodomira [7]

Answer:

D. 30 Ω

Explanation:

R₁ + R₂ = 33

-0.0005 R₁ + 0.005 R₂ = 0

Solve the system of equations for R₁.

-0.0005 R₁ + 0.005 R₂ = 0

0.005 R₂ = 0.0005 R₁

R₂ = 0.1 R₁

R₁ + R₂ = 33

R₁ + 0.1 R₁ = 33

1.1 R₁ = 33

R₁ = 30

3 0
3 years ago
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