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arlik [135]
2 years ago
8

I really need help with these questions. Please help.

Chemistry
2 answers:
snow_tiger [21]2 years ago
5 0
Going with A C and B as well hope this helps
Vedmedyk [2.9K]2 years ago
4 0
2 A
3 C
4 B
That were the answers to mine
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At 25 celsius, 1.00 ,ole of O2 was found to occupy a volume of 12.5 L at a pressure of 198 kPa. What value of the gas constant i
mr Goodwill [35]

Answer:

R=8.301\frac{L*kPa}{mol*K}

Explanation:

Hello,

In this case, assuming oxygen as an ideal gas, it is described by:

PV=nRT

Whereas the gas constant R is required, therefore, it is computed as shown below:

R=\frac{PV}{nT} =\frac{198kPa*12.5L}{1.00mol*(25+273.15)K} \\\\R=8.301\frac{L*kPa}{mol*K}

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4 0
3 years ago
How many grams of Co are needed to react with an excess of fe203 to produce 156.2 g FE? show your work.
Gekata [30.6K]

The reaction is given as

Fe2O3 (s)+ 3CO(g)--->3CO2(g)+ 2Fe(s)

No.of moles=mass in gram/molar mass

As for Fe mole =156.2g/55.847=2.7969~2.797

The ratio b/w CO and Fe is 3:2

Moles of CO needed= 2.797x3/2=4.1955

Mass of CO needed= 4.195mol x 28.01g/mol= 117.515g

8 0
3 years ago
In which layer(s) would a solid cube with 6 cm sides and mass of 270 g float? Explain.
DIA [1.3K]
The buoyancy of an object is dictated by its density. So let us calculate for density, where:density = mass / volume
Calculate the volume first of a solid cube:volume = (6 cm)^3 = 216 cm^3 = 216 mL
Therefore density is:density = 270 g / 216 mLdensity = 1.25 g / mL
Therefore this object will float in the layer in which the density is more than 1.25 g / mL.
6 0
3 years ago
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