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Rom4ik [11]
3 years ago
9

A rock is thrown down with an initial speed of 25.3 m/s from a bridge to the water below. It takes 2.29 s for the rock to hit th

e water. How high is the bridge above the water in meters?
Physics
1 answer:
Rzqust [24]3 years ago
7 0
<h2>Height of bridge is 83.66 m</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 25.3 m/s

        Acceleration, a = 9.81 m/s²  

        Time, t = 2.29 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 25.3 x 2.29 + 0.5 x 9.81 x 2.29²

                      s = 83.66 m

      Height of bridge is 83.66 m

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A force of 7.50 N is applied to a spring whose spring constant is .298 N/cm. Find it’s length
gizmo_the_mogwai [7]

Answer:

to find the length just divide 7.50 and . 298

5 0
3 years ago
A soap bubble, when illuminated with light of frequency 5.27 Hz × 1014 Hz, appears to be especially reflective. If it is surroun
denis23 [38]

Answer:

1.07004\times 10^{-7}\ m

Explanation:

n_s = Refractive index of bubble = 1.33

f = Frequency of light = 5.27\times 10^{14}\ Hz

c = Speed of light = 3\times 10^8\ m/s

The wavelength of light is given by

\lambda=\dfrac{2n_st}{m-\dfrac{1}{2}}

Wavelength is also given by

\lambda=\dfrac{c}{f}

m = 1 for minimum thickness

\dfrac{c}{f}=\dfrac{2n_st}{m-\dfrac{1}{2}}\\\Rightarrow t=\dfrac{m-\dfrac{1}{2}c}{2n_sf}\\\Rightarrow t=\dfrac{(1-\dfrac{1}{2})\times 3\times 10^8}{2\times 1.33\times 5.27\times 10^{14}}\\\Rightarrow t=1.07004\times 10^{-7}\ m

The minimum thickness is 1.07004\times 10^{-7}\ m

4 0
3 years ago
The brakes on your automobile are capable of creating a deceleration of 5.0 m/s2. If you are going 135 km/h and suddenly see a s
poizon [28]

Answer:

3.33 seconds

Explanation:

We can use the velocity formula [ v = u + at ] to solve.

Find the value "u".

135km/h -> 135km*1000m/3600s -> 37.5m/s

Find the value "v".

75km/h -> 75km*1000m/3600s -> 20.83m/s

Keep in mind we are dealing with "deceleration" so when we input 5.0m/s into the formula, it will be a negative value.

Now, find "t" which is the value we aren't given with the values we're given in the question.

20.83 = 37.5 - 5t

-16.67 = -5t

3.33 = t

Best of luck!

8 0
3 years ago
(c) Nail tips exert tremendous pressures when they are hit by hammers because they exert a large force over a small area. What f
ziro4ka [17]

Answer:

Force, F = 2356.19 N

Explanation:

Given that,

Diameter of the circular tip, d = 1 mm = 0.001 m

Its radius, r = 0.0005 m

Pressure created, P=3\times 10^9\ N/m^2

To find,

Force exerted on the nail.

Solution,

The pressure exerted by an object is equal to the force acting per unit area. Its formula is given by :

P=\dfrac{F}{A}

F=P\times A

F=3\times 10^9\ N/m^2\times \pi (0.0005\ m)^2

F = 2356.19 N

Therefore, the force exerted on the nail is 2356.19 N.

6 0
3 years ago
Based on the Law of Conservation of Matter, what number should be placed in the box to balance the chemical equation below?
Rashid [163]

Answer:

2

Explanation:

Step 1: RxN

4Al + 3O₂ → Al₂O₃

Step 2: Balance RxN

We have 4 Al's and 6 O₂'s on the reactant side.

We need the same number of Al's and O₂'s on the product side.

4Al + 3O₂ → 2Al₂O₃

7 0
3 years ago
Read 2 more answers
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