Answer:
The answer is
<h2>28 kg</h2>
Explanation:
The mass of an object given it's momentum and velocity / speed can be found by using the formula

where
m is the mass
p is the momentum
v is the speed or velocity
From the question
p = 280 kg/ms
v = 10 m/s
The mass of the object is

We have the final answer as
<h3>28 kg</h3>
Hope this helps you
Answer:
14.36 N
Explanation:
= Tension in string 1
= Tension in string 2
= mass of the bar = 2.7 kg
= weight of the bar
weight of the bar is given as
N
= mass of the bar = 1.35 kg
= weight of the monkey
weight of the monkey is given as
N
Using equilibrium of torque about left end
N
Using equilibrium of force in vertical direction
N
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
There should be an image that should accompanied your question, I was able to chcek it from other sources. the acceleration of the block when the scale reads 32N is <span>4.0 m/s*s</span>
Complete Question
Suppose you have three identical metal spheres, A, B, and C. Initially sphere A carries a charge q and the others are uncharged. Sphere A is brought in contact with sphere B, and then the two are separated. Spheres CC and BB are then brought in contact and separated. Finally spheres AA and CC are brought in contact and then separated. What is the final charge on the sphere B, in terms of q?
a. 3/8q
b. 1/4q
c. 3/4q
d. q
e. 5/8q
f. 1/3q
g.1/2q
h. 0
Answer:
The correct option is b
Explanation:
From the question we are told that
The charge carried by A is q C
The charge carried by B is 0 C
The charge carried by C is 0 C
When A and B are brought close and then separated the charge carried by A and B is mathematically evaluated as

When C and B are brought close and then separated the charge carried by C and B is mathematically evaluated as

When C and A are brought close and then separated the charge carried by C and A is mathematically evaluated as

Looking at these calculation we can see that the charge carried by B is
