Kinetic energy is the energy possessed by an object on motion. it is expressed as follows:
KE = 0.5mv^2
where m is the mass and v is the velocity of the object. We calculate as follows:
KE = 0.5mv^2
1.1x10^9 J = 0.5(8.0x10^4 kg) v^2
v = 165.83 m/s
Answer:
The net emissions rate of sulfur is 1861 lb/hr
Explanation:
Given that:
The power or the power plant = 750 MWe
Since the power plant with a thermal efficiency of 42% (i.e. 0.42) burns 9000 Btu/lb coal, Then the energy released per one lb of the coal can be computed as:

= 3988126.8 J
= 3.99 MJ
Also, The mass of the burned coal per sec can be calculated by dividing the molecular weight of the power plant by the energy released per one lb.
i.e.
The mass of the coal that is burned per sec 
The mass of the coal that is burned per sec = 187.97 lb/s
The mass of sulfur burned 
= 2.067 lb/s
To hour; we have:
= 7444 lb/hr
However, If a scrubber with 75% removal efficiency is utilized,
Then; the net emissions rate of sulfur is (1 - 0.75) × 7444 lb/hr
= 0.25 × 7444 lb/hr
= 1861 lb/hr
Hence, the net emissions rate of sulfur is 1861 lb/hr
Answer:
B, it includes a control group and an experimental group.
The net force on the bike and the rider is 120 N
Explanation:
We can solve this problem by applying Newton's second law of motion, which states that:
F = ma
where
F is the net force exerted on an object
m is the mass of the object
a is its acceleration
For the bike and the rider in this problem, we have
m = 60 kg is their combined mass
is their acceleration
Therefore, the net force on them is

Learn more about Newton's second law:
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Answer:
Acceleration, 
Explanation:
It is given that,
Force acting on the object across a smooth surface, F = 10 N
Mass of the object, m = 6 kg
Let a is the acceleration of the object. The forces acting on teh object is given by :
F = ma



So, the acceleration of the object is
. Hence, this is required solution.