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Pie
2 years ago
11

An ac series circuit contains a resistor of 15 ohms, an inductor of 11.5 mH and a variable capacitor. If the frequency of the ap

plied voltage is 330 Hz, to what setting should the capacitor be set if resonance is achieved? A) 54.945 μF B) 64.35 μF C) 20.23 μF D) 11 μF E) 55.2 μF
Physics
1 answer:
SpyIntel [72]2 years ago
5 0

Answer:

C) 20.23 μF

Explanation:

R = resistance of the resistor = 15 ohm

L = inductance of the inductor = 11.5 mH = 0.0115 H

f = resonance frequency achieved = frequency of applied voltage = 330 Hz

C = Capacitance of the capacitor

For resonance to be possible

2\pi fL = \frac{1}{2\pi fC}

2(3.14) (330) (0.0115) = \frac{1}{2 (3.14) (330) C}

C = 20.23 x 10⁻⁶ F

C = 20.23 μF

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Answer:

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From the question we are told that  

    The force is  F = 187 \ lb

     The angle made with second force \theta_o = 73 ^o 36' =  73 + \frac{36}{60}  =  73.6^o

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For us to solve problem we are going to assume that

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     R = \sqrt{187^2 + 129.9 ^2  + 2 (187 ) (129.9) cos (73.6)}

     R = 256.047 N

 

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