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makvit [3.9K]
2 years ago
15

Identify the structure of a minor product formed from the radical chlorination of propane, which has molecular formula C3H6Cl2 a

nd exhibits the given 1H NMR spectrum.

Chemistry
1 answer:
Novosadov [1.4K]2 years ago
7 0

Answer:

             As we are not provided with ¹H-NMR spectrum therefore we can not conclude a single result for the minor chlorination of propane with Molecular formula C₃H₆Cl₂.

Hence, we will draw all the possible isomers with molecular formula C₃H₆Cl₂ and predict the ¹H-NMR spectrum for each of them separately.

Below is the structures of possible minor products and the NMR spectrum respectively.

Possible Product A:

                                If the minor product formed is 2,2-Dichloropropane then it will give only one singlet peak in NMR spectrum.

Possible Product B:

                               If the minor product is 1,1-Dichloropropane then it will exhibit two triplets and one multiplet as shown in figure.

Possible Product C:

                               If the minor product is 1,2-Dichloropropane then it will give four peaks in NMR. The extra peak is formed due to two enantiomers about the chiral carbon.

Possible Product D:

                               If the minor product is 1,3-Dichloropropane then it will exhibit one triplet and one quintet signal as shown in figure.

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The half life of oxygen is 2 minutes. What fraction of a sample of 0.15 will remain after 5 half lives?​
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Explanation:

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Original amount (N₀) = 0.15

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Next, we shall determine the amount remaining (N) after 5 half-life. This can be obtained as follow:

Amount remaining (N) = 1/2ⁿ × original amount (N₀)

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Fraction remaining = 4.69×10¯³/0.15 × 100

Fraction remaining = 3.13%

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