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makvit [3.9K]
3 years ago
15

Identify the structure of a minor product formed from the radical chlorination of propane, which has molecular formula C3H6Cl2 a

nd exhibits the given 1H NMR spectrum.

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
7 0

Answer:

             As we are not provided with ¹H-NMR spectrum therefore we can not conclude a single result for the minor chlorination of propane with Molecular formula C₃H₆Cl₂.

Hence, we will draw all the possible isomers with molecular formula C₃H₆Cl₂ and predict the ¹H-NMR spectrum for each of them separately.

Below is the structures of possible minor products and the NMR spectrum respectively.

Possible Product A:

                                If the minor product formed is 2,2-Dichloropropane then it will give only one singlet peak in NMR spectrum.

Possible Product B:

                               If the minor product is 1,1-Dichloropropane then it will exhibit two triplets and one multiplet as shown in figure.

Possible Product C:

                               If the minor product is 1,2-Dichloropropane then it will give four peaks in NMR. The extra peak is formed due to two enantiomers about the chiral carbon.

Possible Product D:

                               If the minor product is 1,3-Dichloropropane then it will exhibit one triplet and one quintet signal as shown in figure.

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5 0
3 years ago
Read 2 more answers
Which of the following is a salt that will form from the combination of a strong base with a weak acid?
zaharov [31]

Answer:

A. NaHCO₃

Explanation:

NaHCO₃ ⇒ NaOH + H₂CO₃

NaOH is a strong base and H₂CO₃ is a weak acid. Therefore, NaHCO₃ is a salt of a strong base-weak acid reaction. The salt is basic because carbonic acid (H₂CO₃) is a weak acid so it remains undissociated. So, there is a presence of additional OH⁻ ions that makes the solution basic.

Hope that helps.

8 0
3 years ago
A manganese electrode was oxidized electrically. If the mass of the electrode decreased by 225 mg during the passage of 1580 cou
qwelly [4]

Answer:

<u>Oxidation state of Mn = +4</u>

Explanation:

Atomic mass of Mn = 55g/mol

From Faraday's law of electrolysis,

Electrochemical equivalent = \frac{mass}{charge}

i.e Z = \frac{m}{Q} = \frac{0.225g}{1580C} = 0.0001424 g/C

But Equivalent weight, E = atomic mass ÷ valency  = Z × 96,485

⇒ \frac{55}{valency} = 0.0001424 × 96,485

<u>∴ Valency of Mn = +4</u>

8 0
3 years ago
The molar solubility of magnesium carbonate is 1.8 × 10–4 mol/l. What is ksp for this compound?
Serhud [2]

Answer:

3.2 × 10⁻⁸

Explanation:

Let's consider the solution of magnesium carbonate.

MgCO₃ ⇄ Mg²⁺(aq) + CO₃²⁻(aq)

We can relate the molar solubility (S) with the solubility product (Ksp) using an ICE chart.

         MgCO₃ ⇄ Mg²⁺(aq) + CO₃²⁻(aq)

I                             0                0

C                          +S              +S

E                            S                S

The Ksp is:

Ksp = [Mg²⁺] × [CO₃²⁻] = S × S = S² = (1.8 × 10⁻⁴)² = 3.2 × 10⁻⁸

4 0
3 years ago
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Is salt a iconically bounded compound?
zvonat [6]

Answer:

i believe u mean "ionically". Yes it is.

Explanation:

3 0
3 years ago
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