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makvit [3.9K]
3 years ago
15

Identify the structure of a minor product formed from the radical chlorination of propane, which has molecular formula C3H6Cl2 a

nd exhibits the given 1H NMR spectrum.

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
7 0

Answer:

             As we are not provided with ¹H-NMR spectrum therefore we can not conclude a single result for the minor chlorination of propane with Molecular formula C₃H₆Cl₂.

Hence, we will draw all the possible isomers with molecular formula C₃H₆Cl₂ and predict the ¹H-NMR spectrum for each of them separately.

Below is the structures of possible minor products and the NMR spectrum respectively.

Possible Product A:

                                If the minor product formed is 2,2-Dichloropropane then it will give only one singlet peak in NMR spectrum.

Possible Product B:

                               If the minor product is 1,1-Dichloropropane then it will exhibit two triplets and one multiplet as shown in figure.

Possible Product C:

                               If the minor product is 1,2-Dichloropropane then it will give four peaks in NMR. The extra peak is formed due to two enantiomers about the chiral carbon.

Possible Product D:

                               If the minor product is 1,3-Dichloropropane then it will exhibit one triplet and one quintet signal as shown in figure.

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How many molecules of copper sulfate are needed to produce 5.0×1024 molecules of sodium sulfate?
lubasha [3.4K]

Answer:

5.0 × 10²⁴ molecules

Explanation:

Step 1: Write the balanced double displacement reaction

2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂

Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄

We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.

5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol

Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄

The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.

Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄

We will use Avogadro's number.

8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule

4 0
3 years ago
For the following reaction, KcKc = 255 at 1000 KK.
bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

                           CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.      0.1550      0.173           0

At eqm.          (0.1550-x)  (0.173-x)         x

As we are given:

K_c=255

The expression for equilibrium constant is:

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get:

255=\frac{(x)}{(0.1550-x)\times (0.173-x)}

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

5 0
3 years ago
True or false? Second level consumers may be carnivore or omnivores
const2013 [10]
Yes this is true because they are able to consume 2 organisms which are plants and animal just like us.
3 0
3 years ago
Which one is you fav one
serious [3.7K]

Answer:

the 3rd one

Explanation:

8 0
3 years ago
Read 2 more answers
From the given elements Na, P , Ca ,Br which one has highest first ionization energy , ,smallest atomic size , most metallic cha
madam [21]

Answer:

highest first ionization energy - Br

smallest atomic size - Br

most metallic character - Na

Explanation:

Ionization energy of Br is higher than P because higher zeff value

Sodium is more metallic than calcium because it is able to loose electron more readily as compared to calcium because of higher electro positivity.

Atomic radius of Br is the smallest as its atomic radius is 114, P (115), Ca (197), Na (186)

 

 

5 0
3 years ago
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