The temperature of a 6.0-g sample of glass changed from 20°C to 45°C when it absorbed 550 J of heat. What is the specific heat o
f this glass sample?
A. 130 J/g•°C
B. 2300 J/g•°C
C. 0.27 J/g•°C
D. 3.7 J/g•°C
2 answers:
The answer is D
the formula you need to use is Q=mc(delta)t the delta is usually written as a triangle
rearrange this to make c the subject as this is the specific heat capacity
so you get c=Q/(m*tempchange)
delta t means temp change btw
plug in you values so 550/(6*25)
and you get 3.666666
to 1 decimal place = 3.7
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