No, more than 1 paratical
Molar mass of sodium chloride is 22.99 g/mol (Na+) + 35.45 g/mol (Cl-) = x g/mol. Then take the mass of sodium chloride sample 5 grams and divide by molar mass to get the number of moles. Take this number and multiply it by Avogadro’s number (6.22*10^23 molecules/mol). You now have the amount of molecules in 5 grams of NaCl.
Answer:
After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M.
Explanation:
Based on the reaction of the problem, you have as general kinetic law for a first-order reaction:
ln[HI] = -kt + ln [HI]₀
<em>Where [HI] is actual concentration after time t, </em>
<em>k is rate constant </em>
<em>and [HI]₀ is initial concentration of the reactant.
</em>
Initial concentration of HI is 0.310M,
K is 0.0660s⁻¹,
And the actual concentration is 0.0558M:
ln[HI] = -kt + ln [HI]₀
ln[0.0558M] = -0.0660s⁻¹*t + ln [
0.310M]
-1.7148 = -0.0660s⁻¹*t
26.0s = t
<h3>After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M</h3>
<em />
Answer:
The concentration of the solution is 1.068×10⁻⁴M
Explanation:
Hello,
To find the concentration of the solution, we'll have to use Beer-Lambert law which states absorption is directly proportional to the concentration of the solution.
Beer-Lambert law = A = εCL
A = absorption = 2 - log₁₀%T = 2 - log₁₀(34)
A = 2 - 1.5314 = 0.47
A = 0.47
ε = molar absorption coefficient = 4400
C = concentration of the solution
L = path length = 1cm
A = εcl
C = A / εl
C = 0.47 / 4400 × 1
C = 1.068×10⁻⁴M
The concentration of the solution is 1.068×10⁻⁴M
