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faltersainse [42]
3 years ago
8

Anna drew a diagram to compare the strong and weak force. Which labels belong in the areas marked X, Y, and Z? X: infinite range

Y: attractive and repulsive Z: very small range X: attractive only Y: very small range Z: attractive and repulsive X: attractive and repulsive Y: infinite range Z: attractive only X: very small range Y: attractive only Z: infinite range
Physics
1 answer:
Maslowich3 years ago
8 0

Answer:

For areas marked X, Y, Z, X is attractive only, Y has a very small range, and Z is attractive and repulsive

Explanation:

Solution

Given that:

From the question stated, Anna drew a diagram to compare forces that are strong and weak.

Now,

We are to find which labels are grouped in areas marked as X, Y, Z respectively.

Thus,

For X, Y, Z it is marked as:

X: Always attractive  or attractive only

Y: Very small range

Z:  Repulsive and attractive

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nlexa [21]

Answer:

437 J

Explanation:

Parameters given:

Weight of child, W = 230 N

Height of swing, h = 1.9 m

Gravitational Potential Energy is given as:

P. E. = m*g*h = W*h

m = mass

h = height above the ground

W = weight

P. E. = 230 * 1.9

P. E. = 437 J

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A house burns down. On the house across the street, all of the vinyl siding is twisted, melted, and warped because of the heat.
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Answer:

Radiation

Explanation:

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A planet with a mass one-half that of Earth has a radius that is 3 times that of Earth's radius. What is the gravitational field
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The gravitational acceleration of a planet is proportional to the planet's mass, and inversely proportional to square of the planet's radius.

So when you stand on the surface of this particular planet, you feel a force of gravity that is

(1/2) / (3²)

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That's <em>(1/18)</em> as much as on Earth.

The acceleration of gravity there would be about <em>0.545 m/s²</em>.  

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3 years ago
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Allisa [31]

Answer:

23.52 m/s

Explanation:

The following data were obtained from the question:

Time taken (t) to reach the maximum height = 2.4 s

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =..?

At the maximum height, the final velocity (v) is zero. Thus, we can obtain how fast the rock (i.e initial velocity)

was thrown as follow:

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