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Wewaii [24]
3 years ago
10

how does the electric force between two charged particles change if the distance between them is increased by a factor of 3? a.

it is reduced by a factor of 3 b. it is increased by a factor of 3 c. it is increased by a factor of 9 d. it is decreased by a factor of 9
Physics
2 answers:
Anna007 [38]3 years ago
6 0
D. it is decreased by a factor of 9.

Force = kqq ÷ r^2

The distance is squared so if it is increased or decreased by any factor, then it must be squared too. Because the distance is on the bottom of the equation, you divide the force by the increasing or decreasing factor.
seropon [69]3 years ago
5 0

Answer: C. It increased by a factor of 9

Explanation:

A P E X

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False

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A 24-V battery is powering a light bulb with a resistance of 3.0 ohms. What is the current flowing through the bulb? A) 7.20 A B
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According to Ohm's law for a portion of the circuit we have:

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Differentiate between earthworm and housefly​
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3 years ago
An RLC circuit is used in a radio to tune into the radio lagos fm Station broadcasting at 93.5Hz. The resistance is 15ohms and t
bazaltina [42]

The characteristics of the RLC circuit allow to find the result for the capacitance at a resonance of 93.5 Hz is:

  • Capacitance is C = 1.8 10⁻⁶ F

A series RLC circuit reaches the maximum signal for a specific frequency, called the resonance frequency, this value depends on the impedance of the circuit.

            Z^2 = R^2 + ( wL - \frac{1}{wC} )^2  

Where Z is the impedance of the circuit, R the resistance, L the inductance, C the capacitance and w the angular velocity. The negative sign is due to the fact that the current in the capacitor and the inductor are out of phase.

In the case of resonance, the impedance term completes the circuit as a resistive system.

           wL - \frac{1}{wC} = 0  \\w^2 = \frac{1}{LC}  

           

Indicate that the inductance L = 1.6 H and the frequency f = 93.5 Hz.

Angular velocity and frequency are related.

         

         w = 2π f

           

Let's  substitute.

          C = \frac{1}{L ( 2 \pi f)^2 }  

 

Let's calculate.

         C = \frac{1}{1.6 \ ( 2\pi \ 93.5)^2}  

         C = 1.8 10⁻⁶ F

In conclusion with the characteristics of the RLC circuits we can find the result for the capacitance at a 93.5 Hz resonance is:

  • Capacitance is C = 1.8 10⁻⁶ F

Learn more about serial RLC circuits here: brainly.com/question/15595203

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