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makvit [3.9K]
3 years ago
12

Does a more efficient car have a larger or smaller LPK number? Explain how you know..

Physics
2 answers:
Sindrei [870]3 years ago
7 0

Answer: smaller

LPK (Litre per kilometer) refers to amount of fuel in litres required per unit km by a car. In Europe, LPK number is used to specify the efficiency of a car. An efficient car would be the one which would consume less amount of fuel per kilometer run. Hence, a more efficient car would have smaller LPK number.

Softa [21]3 years ago
5 0

A more efficient car will have smaller LPK number.

Explanation

LPK number is the measure of liters of fuel consumed by the vehicle to travel one kilometer distance.

The LPK number that is liters per kilometer number is used in Europe to determine the efficiency of cars.

A car will be termed as efficient if it uses less amount of fuel for travelling a larger distance.

This indicates that car which has more mileage or in other word which consumes less quantity of fuel to travel longer distance is termed as efficient cars.

Thus , a more efficient car will have smaller LPK number.

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If a train is 100 kilometers away, how much sooner would you hear the train coming by listening to the rails (iron) as opposed t
Whitepunk [10]
From tables, the speed of sound at 0°C is approximately
V₁ = 331 m/s (in air)
V₃ = 5130 m/s (in iron)

Distance traveled is
d = 100 km = 10⁵ m

Time required to travel in air is
t₁ = d/V₁ = 10⁵/331 = 302.12 s

Time required to travel in iron is
t₂ = d/V₂ = 10⁵/5130 = 19.49 s

The difference in time is
302.12 - 19.49 = 282.63 s

Answer:  283 s (nearest second)



6 0
3 years ago
Which of the following represents a chemical change to matter? A. digestion of food B. melting an ice cube C. shredding paper D.
guajiro [1.7K]
The answer is A. digestion of food. The chemical change to matter means that the molecule structure has been destroyed. For B, C and D. the matter are still ice, paper and ice. So they are physical change.
8 0
3 years ago
Estimate the electric field at a point 2.40 cm perpendicular to the midpoint of a uniformly charged 2.00-m-long thin wire carryi
nadya68 [22]

Answer:

E = 1.85*10^{12}\frac{N}{C}

Explanation:

Hi!

The perpendicular distance 2.4cm, is much less than the distance to both endpoints of the wire, which is aprox 1m. Then the edge effect is negligible at this field point, and we can aproximate the wire as infinitely long.

The electric filed of an infinitely long wire is easy to calculate. Let's call z the axis along the wire. Because of its simmetry (translational and rotational), the electric field E must point in the radial direction,  and it cannot depende on coordinate z. To calculate the field Gauss law is used, as seen in the image, with a cylindrical gaussian surface. The result is:

E = \frac{\lambda}{2\pi \epsilon_0 r}\\\lambda=\text{charge per unit length}=\frac{4.95 \mu C}{2 m} = 2.475 \frac{C}{m}\\r=\text{perpendicular distance to wire}\\\epsilon_0=8.85*10^{-12}\frac{C^2}{Nm^2}

Then the electric field at the point of interest is estimated as:

E = \frac{\22.475}{2\pi*( 8.85*10^{-12})*(2.4*10^{-2})}\frac{N}{C}=1.85*10^{12}\frac{N}{C}

6 0
4 years ago
A boy jumps from a wall 3m high. What is an estimate of the change in momentum of the boy when he lands without rebounding?
EastWind [94]
The answer is D. Because the boy jump 3 high
8 0
3 years ago
roblem 10: In an adiabatic process oxygen gas in a container is compressed along a path that can be described by the following p
miskamm [114]

Answer:

W= -2.5 (p₁*0.0012) joules

Explanation:

Given that p₀= initial pressure, p₁=final pressure, Vi= initial volume=0 and Vf=final volume= 6/5 liters where p₁=p₀ then

In adiabatic compression, work done by mixture during compression is

W= \int\limits^f_i {p} \, dV  where f= final volume and i =initial volume, p=pressure

p can be written as p=K/V^γ where K=p₀Vi^γ =p₁Vf^γ

W= \int\limits^f_i {K/V^} \, dV

W= K/1-γ ( 1/Vf^γ-1 - 1/Vi^γ-1)

W=1/1-γ (p₁Vf-p₀Vi)

W= 1/1-1.40 (p₁*6/5 -p₀*0)  

W= -2.5 (p₁*6/5*0.001)   changing liters to m³

W= -2.5 (p₁*0.0012) joules

3 0
3 years ago
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