Answer:
Explanation:
From the question we are told that
The number of slits per cm is k = 
The order of the maxima is n = 1
The wavelength are 
The spacing between the slit is mathematically represented as
=> 
=> 
Generally the condition for constructive interference is
At 
![\theta _1 = sin^{-1} [ \frac{1 * 434 *10^{-9}}{6.211 *10^{-5}} ]](https://tex.z-dn.net/?f=%5Ctheta%20_1%20%20%3D%20%20sin%5E%7B-1%7D%20%5B%20%5Cfrac%7B1%20%20%2A%20%20434%20%2A10%5E%7B-9%7D%7D%7B6.211%20%2A10%5E%7B-5%7D%7D%20%5D)
At 
![\theta _2 = sin^{-1} [ \frac{1 * 410 *10^{-9}}{6.211 *10^{-5}} ]](https://tex.z-dn.net/?f=%5Ctheta%20_2%20%20%3D%20%20sin%5E%7B-1%7D%20%5B%20%5Cfrac%7B1%20%20%2A%20%20410%20%2A10%5E%7B-9%7D%7D%7B6.211%20%2A10%5E%7B-5%7D%7D%20%5D)
Answer:
False
Explanation:
This is due to the gravitational pull, since the moon does not have the same force or gravity like Earth, your weight would change.
☆anvipatel77☆
•Expert•
Brainly Community Contributor
With the switch open, there's no current in the circuit, and therefore
no voltage drop across any of the dissipative elements (the resistor
or the battery's internal impedance). So the entire battery voltage
appears across the switch, and the voltmeter reads 12.0V .
Properties of electromagnetic radiation and photons. ... we find the types of energy that are lower in frequency ( and thus longer in wavelength) than visible light. Seeee
Answer:
(C) The frequency decrease and intensity decrease
Explanation:
The Doppler effect describes the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source, or the wave source is moving relative to the observer, or both.
if the observer and the source move away from each other as is the case for this problem, the wavelength heard by the observer is bigger.
The frequency is the inverse from the wavelength, so the frequency heard will increase.
The sound intensity depends inversely on the area in which the sound propagates. When the buzzer is close, the area is from a small sphere, but as the buzzer moves further away, the wave area will be from a larger sphere and therefore the intensity will decrease.
