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LekaFEV [45]
3 years ago
11

A 2.5-m-long tension member (E = 70 GPa) has cross-sectional dimensions of 25 mm x 35 mm. Determine the maximum load P that may

be supported by this member if the allowable normal stress may not exceed 90 MPa and the total elongation must not exceed 3 mm. State your answer in kN.
Physics
1 answer:
Alja [10]3 years ago
8 0

Answer:

Force = 7.3 kN

Explanation:

Elastic Modulus = Stress / Strain

Since the maximum stress applied can be 90 MPa, lets check the corresponding maximum strain using the above equation.

70 * 10^9 = 90 * 10^6 / Strain

Strain = 0.0012857

Strain = Change in length/total length

Change in Length = 0.0012857 * 2.5

Change in Length = 0.003214 m

Converted to mm this is: 0.003214 * 1000 = 3.214 mm

Thus we can see that strain is the limiting factor, and not stress. This is because with the maximum stress possible applied, we go over the strain limit.

Doing another quick calculation, we can take out the maximum stress with strain equal to 3mm/2.5m

Strain = (3/1000)/2.5

Strain = 0.0012

Modulus of elasticity = Stress/ Strain

Stress = 70 * 10^9 * 0.0012

Stress = 84 MPa

This stress is under both the strain and stress limit.

Taking out the force due to this stress:

Stress = force / area

Force = 84 * 10^6 * Area

Force = 84 * 10^6 * (25/1000) * (35/1000)

Force = 7350 N or 7.3 kN

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A 69 kg driver gets into an empty taptap to start the day's work. The springs compress 2×10−2 m . What is the effective spring c
natulia [17]

Answer:

3.4\cdot 10^4 N/m

Explanation:

The spring system in the taptap obey's Hooke's law, which states that:

F=kx

where

F is the magnitude of the force applied

k is the spring constant

x is the compression/stretching of the spring

In this problem:

- The force applied is the weight of the driver of mass m = 69 kg, so

F=mg=(69 kg)(9.8 m/s^2)=676.2 N

- The compression of the spring is

x=2\cdot 10^{-2} m=0.02 m

So, the spring constant is

k=\frac{F}{x}=\frac{676.2 N}{0.02 m}=3.4\cdot 10^4 N/m

3 0
3 years ago
At 45 degrees s latitude, the angle of the noon sun is lowest and the length of daylight is shortest on:
Marat540 [252]

Answer;

- June 21

At 45 degrees latitude, the angle of the noon sun is lowest and the length of daylight is shortest on June 21.

Explanation;

-On June 21 you will note that the Northern Hemisphere is pitched toward the Sun. This means that the Sun's vertical ray is striking the Earth at the Tropic of Cancer (23.5 degrees N).

-Days tend to get longer in the northern hemisphere from December 21 to June 21, and then grow shorter from June 21 to December 21.  The June solstice is the summer solstice in the Northern Hemisphere and the winter solstice in the Southern Hemisphere. The date varies between June 20 and June 22, depending on the year, and the local time zone.

8 0
3 years ago
A dentist’s drill starts from rest. After 1.46 sof constant angular acceleration, it turns at arate of 27000 rev/min.Find the dr
Black_prince [1.1K]

Answer:

616.3 rad/s²

Explanation:

Given that

t= 1.46 s

Initial angular velocity ,ωi = 0 rad/s

Final angular velocity ωf= 27000 rev/min

Angular speed in the rad/s given as

\omega_f=\dfrac{2\pi N}{60}\ rad/s

Now by putting the values

\omega_f=\dfrac{2\times 27000}{60}\ rad/s

ωf=900 rad/s

We know that (if acceleration is constant)

ωf=ωi + α t

α=Angular acceleration

900 = 0 + α x 1.46

\alpha=\dfrac{900}{1.46}\ rad/s^2\\\alpha=616.43\ rad/s^2

Therefore the acceleration will be 616.3 rad/s²  

4 0
3 years ago
A wave with a frequency of 500 Hz is traveling at a speed of 200 m/s. What is the wavelength?
pshichka [43]

Answer:0.4 is what i got

Explanation:

200÷500

6 0
3 years ago
A proton is held at rest in a uniform electric field. When it is released, the proton will lose?
nydimaria [60]

A proton is held at rest in a uniform electric field. When it is released, the proton will lose its kinetic energy.

Kinetic energy

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort when slowing down from its current pace to a condition of rest. Formally, kinetic energy is any term that includes a derivative with respect to time in the Lagrangian of a system.

To learn more about kinetic energy refer here:

brainly.com/question/11301578

#SPJ4

5 0
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