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snow_lady [41]
2 years ago
9

Identify the energy transformation that occurs in the light bulb of a lamp:

Physics
1 answer:
vekshin12 years ago
3 0

Answer:

In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy. Chemical energy in the batteries is transferred into electrical energy.

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The force of attraction that holds two atoms together within a molecule is
makvit [3.9K]

Answer: The force of attraction that holds two molecules is a chemical bond

Explanation:

What is Chemical bonds?

Chemical bonds are forces that hold atoms together to make compounds or molecules.

Types of chemical bonds

Chemical bonds include

1.covalent,

2. polar covalent, and

3. ionic bonds.

Atoms with relatively similar electronegativities share electrons between them and are connected by covalent bonds.

5 0
2 years ago
I need help with this
Fed [463]
HEY THERE !!

It is called SUBLIMATION.

so the correct answer is (D).
3 0
2 years ago
Read 2 more answers
A constant net force of 20 N is applied to a 32kg car, causing it to speed up from 4.0 to 9.0 m/s. How long is the force applied
pishuonlain [190]

Answer:

8 seconds

Explanation:

From Newton's second law;

Ft = m(v-u)

F = Force applied

t = time taken

v = final velocity

u  = initial velocity

20 * t = 32 (9 - 4)

20t = 32 * 5

t = 32 * 5/ 20

t = 8 seconds

8 0
2 years ago
Calculate Speed The 2-kg metal ball moving at a speed of 3 m/s strikes a 1-kg wooden ball that is at rest. After the collision,
enot [183]

Answer:

53466kg.

Explanatiokn:

5 0
1 year ago
If it takes a ball dropped from rest 2.261 s to fall to the ground, from what height H was it released? Express your answer in m
algol [13]

Answer:

Height, H = 25.04 meters

Explanation:

Initially the ball is at rest, u = 0

Time taken to fall to the ground, t = 2.261 s

Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :

H=ut+\dfrac{1}{2}at^2

Here, a = g

H=\dfrac{1}{2}gt^2            

H=\dfrac{1}{2}\times 9.8\times (2.261)^2

H = 25.04 meters

So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.

7 0
2 years ago
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