Answer:
True
Explanation:
the horse pull on the wagon but friction and the wight + gravity make the wagon pull on the horse ( newton's 2ed law)
Acceleration = v-u/t
= (45-30)/15
= 1 km/h
Distance = ut + 1/2 at^2
s = [30 x 15] + 1/2 x 1 x 15^2
= 562.5 km
Hope this helps
Answer:
30.7m
Explanation:
You can use the following equation:
ρ = R * 
Where ρ is the resistivity, R is the resistance, S is the Cross-sectional Area and l is the length of the wire.
We issolate l in the equation and solve with the data we have:
l = R * 
= 3.25 Ω * 
l = 30.7m
Hooke's law states that for a helical spring the extension is directly proportional to the force applied provided the elastic limit is not exceeded.
Therefore; F= ke, where k is the spring constant, F is the force and e is the extension.
k = 2700 N/m and e = 3 cm or 0.03 M
therefore, F = 2700 × 0.03
= 81 N
Thus, the force required will be 81 N
