The final velocity of the other student after the elastic collision with Logan is 6.94 m/s.
<h3>
Conservation of linear momentum</h3>
The final velocity of the other student will be determined by applying the principle of conservation of linear momentum for elastic collision.
- let u represent initial velocity
- let v represent final velocity
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Substitute the given parameters and solve for final velocity of the other stsudent.
74(7.6) + 81(0) = 74(0) + 81(v₂)
562.4 = 81v₂
v₂ = 562.4/81
v₂ = 6.94 m/s
Thus, the final velocity of the other student after the elastic collision with Logan is 6.94 m/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
the answer is B
Explanation:
we assume that all of these springs have tha same k , the spring constant
elastic energy for the initial system = Ep1=
for the new changed system , the spring constant = k1+k2 = k+k = 2k , but the displacement is also reduced to 0.5 d
so Ep2 =
so the new total Ep stored in the new system is 1/2Ep
hope it helps
To solve this we assume
that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas
equation which is expressed as PV = nRT. At a constant pressure and number of
moles of the gas the ratio T/V is equal to some constant. At another set of
condition of temperature, the constant is still the same. Calculations are as
follows:
T1 / V1 = T2 / V2
V2 = T2 x V1 / T1
V2 = 308 K x 556 cm³ / 278 K
<span>V2 = 616 cm</span><span>³</span>
Answer:
350 N
Explanation:
From the question given above, the following data were obtained:
Mass (m) of Go Kart = 35 kg
Initial velocity (u) = 12 m/s
Distance (s) = 7.2 m
Force (F) =?
Next, we shall determine the acceleration of the Go Kart. This can be obtained as follow:
Initial velocity (u) = 12 m/s
Distance (s) = 7.2 m
Final velocity (v) = 0 m/s
Acceleration (a) =.?
v² = u² + 2as
0² = 12² + (2 × a × 7.2)
0 = 144 + 14.4a
Collect like terms
0 – 144 = 14.4a
– 144 = 14.4a
Divide both side by 14.4
a = – 144 / 14.4
a = – 10 m/s²
The negative sign indicate that the Go Kart is decelerating when the brake was applied.
Finally, we shall determine the force the Go Kart have when the student locked the brake. This can be obtained as follow:
Mass (m) of Go Kart = 35 kg
Acceleration (a) = 10 m/s
Force (F) =?
F = ma
F = 35 × 10
F = 350 N
Thus, the Go Kart has a force of 350 N when the student locked the brake.
Http://www.kyrene.org/cms/lib2/AZ01001083/Centricity/Domain/2932/Peppered%20Moth%20and%20Galapados%20Island%20PowerPoint.pptx
This should lead you to correct answer