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4 years ago

Four seismometers stations are the minimum needed to calculate the epicenter of an earthquake.

Physics

1 answer:

Gelneren [198K]4 years ago

4 0

Answer:

False, Four seismometer statitons are no required to find the earthquake's epicenter.

Explanation:

The least number of seismometer stations sufficient for finding the epicenter of earthquake is three. Epicenter is point on earth's crust from where the seismic rupture gets originated. Using the distances to the epicenter from atleast three seismometers the epicenter of earthquake can be determined. This distance is used as the radius and 3 circles are drawn. The point at which the 3 circles intersect is called as epicenter of the earthquake. With one seismometer station, we can determine only the distance to the epicenter. With two seismometer station, measurements are ambiguous. Using more than three seismometer stations produces redundant information. Hence three seismometer is sufficient to determine the epicenter of earthquake.

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If a body of 2kg mass is at a distance of 7200km from the center of the earth .What

wlad13 [49]

None of the choices is correct.

== The Earth's radius is 6,371 km. That's how far you are from the center of the Earth when you're on the ground.

== The acceleration of gravity on the ground is 9.8 m/s² .

== The acceleration of gravity varies inversely as the square of the distance from the center of the Earth. So, at 7,200 km from the center, it's

(9.8 m/s²) · (6371km/7200km)² .

Stuffing this through your cakulator, you'll get 7.67 m/s² .

3 0

3 years ago

A net force of 25N causes an object to accelerate at 4m/s^2. what is the mass of the object?

Doss [256]

Answer:

6.25 kg

Explanation:

Fnet=ma

m=Fnet/a

m=25/4

m=6.25kg

3 0

3 years ago

A rocket accelerates at 25m/s^2 for 5s before it runs out of fuel and dies. What is the maximum height reached by the rocket?

sineoko [7]

Answer:

1109m

Explanation:

The distance h₁ traveled by the rocket during acceleration:

$h_1=\frac{1}{2}at^2$

The velocity v₁ at this height h₁:

$v_1=at$

When the rocket runs out of fuel, energy is conserved:

$E=\frac{1}{2}mv_1^2+mgh_1=mgh_2$

Solving for h₂:

$h_2=\frac{v_1^2}{2g}+h_1=\frac{(at)^2}{2g}+\frac{1}{2}at^2$

8 0

3 years ago

a pulley is used to lift a 2000 N safe over frosty's head. the safe is lifted 6m in 4s by Rudolph. how much power did Rudolph us

garri49 [273]

Answer:

3000W

Explanation:

Given parameter:

Weight of safe = 2000N

Height of lift = 6m

Time = 4s

Unknown:

Power used by Rudolph = ?

Solution:

Power is the rate at which work is being done. It is expressed as:

Power = $\frac{Work done }{Time taken}$

Work done = Weight x height = 2000 x 6 = 12000J

Power = $\frac{12000}{4}$ = 3000W

8 0

3 years ago

The sun's radiation has different wavelengths. the shorter is the radiation's wavelength, the weaker is the radiation's energy.

NeX [460]

It is false. Because the amount of energy carried in the wave is inversely related to the length of the waves wavelength. To correct the statement it should be that the shorter the radiation's wavelength the stronger is the radiation's energy.

7 0

3 years ago