Answer:
t= 9.79 hr
Explanation:
Given that
V= 3.5 V
Capacity= 4 Amp-hour
We know that
V= IR
V= Voltage
I =Current
R=Resistance
V = I R
The total voltage on the batteries will be 2 V
2 x 3.5 = I x 10
I= 0.7 A
We know that Power P
P = V I
P = 0.7 x 7
P =4.9 W
4 A.h and 12 volt power supply = 4 x 12 = 48 W.hr
So time of drain t
4.9 t = 48
t= 9.79 hr
Answer:
The first step is to identify the need and constraints
Explanation:
Multiply the coefficient by the change in temperature:
1.1*10^-5 x (37-5.2) = 0.0003498
Multiply Young's modulus by the area by the above answer:
2*10^11 x 52 * 0.0003498 x (1/100)^2 = 3.63792 x 10^5 N
Answer:
2
Explanation:
my sister did this and its the answer
Answer:
a)
, b)
, c) 
Explanation:
a) The tank can be modelled by the Principle of Mass Conservation:

The mass flow rate exiting the tank is:



b) An expression for the specific enthalpy at outlet is derived from the First Law of Thermodynamics:


Properties of water are obtained from tables:



The specific enthalpy at outlet is:


c) After a quick interpolation from data availables on water tables, the final temperature is:
