Ask question

Ask question

All categories

White raven [17]

2 years ago

8

A 5stage single pipeline computer uses the pipeline mentioned in the lecture (not the book). It resolves the direction and targ

et of a conditional branch instruction at the end of its third pipeline stage. When a branch is detected, the pipeline quashes the subsequent instructions already in the pipeline and stalls until the branch is resolved. After that, execution resumes at the target or the fall-through instruction, based on the branch condition. How many cycles does the pipeline stall upon a branch? (i.e, how many cycles are lost?)

1 answer:

brilliants [131]2 years ago

7 0

I have no idea sorry

You might be interested in

Assign deliveryCost with the cost (in dollars) to deliver a piece of baggage weighing baggageWeight. The baggage delivery servic

Sholpan [36]

Answer: y = x * 1dollars - 30dollars

Explanation:

Giving that the delivery cost in dollar is potent for all x > = 50 pounds of wght

Y = (x - 50)*1 dollar + c ...equ 1

Y = delivery cost equation in dollars

x = weigt of baggage for delivery

c = 20dollars = down payment for the first 50 pound weight of baggage

Equ 1 becomes

Y = (x)dollars - 50 dollars + 20 dollars

Y = (x) dollars -30 dollars

4 0

3 years ago

H2O enters a conical nozzle, operates at a steady state, at 2 MPa, 300 oC, with the inlet velocity 30 m/s and the mass flow rate

Colt1911 [192]

Answer:

The flow velocity at outlet is approximately 37.823 meters per second.

The inlet radius of the nozzle is approximately 0.258 meters.

Explanation:

A conical nozzle is a steady state device used to increase the velocity of a fluid at the expense of pressure. By First Law of Thermodynamics, we have the energy balance of the nozzle:

Energy Balance

$\dot m \cdot \left[\left(h_{in}+\frac{v_{in}^{2}}{2} \right)-\left(h_{out}+\frac{v_{out}^{2}}{2} \right)\right]= 0$ (1)

Where:

$\dot m$ - Mass flow, in kilograms per second.

$h_{in}$ , $h_{out}$ - Specific enthalpies at inlet and outlet, in kilojoules per second.

$v_{in}, v_{out}$ - Flow speed at inlet and outlet, in meters per second.

It is recommended to use water in the form of superheated steam to avoid the appearing of corrosion issues on the nozzle. From Property Charts of water we find the missing specific enthalpies:

Inlet (Superheated steam)

$p = 2000\,kPa$

$T = 300\,^{\circ}C$

$h_{in} = 3024.2\,\frac{kJ}{kg}$

$\nu_{in} = 0.12551\,\frac{m^{3}}{kg}$

Where $\nu_{in}$ is the specific volume of water at inlet, in cubic meters per kilogram.

Outlet (Superheated steam)

$p = 600\,kPa$

$T = 160\,^{\circ}C$

$h_{out} = 2758.9\,\frac{kJ}{kg}$

If we know that $\dot m = 50\,\frac{kJ}{kg}$ , $h_{in} = 3024.2\,\frac{kJ}{kg}$ , $h_{out} = 2758.9\,\frac{kJ}{kg}$ and $v_{in} = 30\,\frac{m}{s}$ , then the flow speed at outlet is:

$35765-25\cdot v_{out}^{2} = 0$ (2)

$v_{out} \approx 37.823\,\frac{m}{s}$

The flow velocity at outlet is approximately 37.823 meters per second.

The mass flow is related to the inlet radius ( $r_{in}$ ), in meters, by this expression:

$\dot m = \frac{\pi \cdot v_{in}\cdot r_{in}^{2} }{\nu_{in}}$ (3)

If we know that $\dot m = 50\,\frac{kJ}{kg}$ , $v_{in} = 30\,\frac{m}{s}$ and $\nu_{in} = 0.12551\,\frac{m^{3}}{kg}$ , then the inlet radius is:

$r_{in} = \sqrt{\frac{\dot m\cdot \nu_{in}}{\pi\cdot v_{in}}}$

$r_{in}\approx 0.258\,m$

The inlet radius of the nozzle is approximately 0.258 meters.

7 0

2 years ago

A current vehicle registration expires at _____ of the first owner listed on the registration form

wariber [46]

Answer:

Midnight on the birthday. Hope this helps!

3 0

2 years ago

ME<br> And what you know about love

antoniya [11.8K]

Answer:

Everything I got what you need

7 0

2 years ago

First person to awnser gets brainlyest!!

Andrews [41]

Answer:

ananswer my question please

7 0

2 years ago

Read 2 more answers