Answer:
t = 6179.1 s = 102.9 min = 1.7 h
Explanation:
The energy provided by the resistance heater must be equal to the energy required to boil the water:
E = ΔQ
ηPt = mH
where.
η = efficiency = 84.5 % = 0.845
P = Power = 2.61 KW = 2610 W
t = time = ?
m = mass of water = 6.03 kg
H = Latent heat of vaporization of water = 2.26 x 10⁶ J/kg
Therefore,
(0.845)(2610 W)t = (6.03 kg)(2.26 x 10⁶ J/kg)
<u>t = 6179.1 s = 102.9 min = 1.7 h</u>
Answer:
1.52 kw
Explanation:
A1 = 0.45
A1 = 0.25
Flow rate = 1.5m³/sec
P1 = 105
P2 = 106
P-air = 1.225kg/m³
I applied bernoulli's equation as I continued (check the attachment)
hp = 83.21371+1.3686 = 84.4823
Pf = p-air x g x Q x hp
Pf = 1.225x9.81x1.5x84.4823
Pf = 1522.868W
When converted to KW we get
Pf = 1.52 KW
Thank you!
Answer:
0.226m or 22.6cm
Explanation:
using the formula: (v = f * lambda), we can rearrange to form (lambda = v / f)
The calculation is 3x10^8/1.33x10^9 which equals 22.6cm to 3 sig fig.
This is assuming the wave mentioned in the question is an electromagnetic wave though, so that we can use a value for the wave's speed. If it was supposed to be another type of wave, the question is not possible without specifying the speed.
Answer:
professionl engineering means and individual who has fufilled academic and experience requirements and permitted by government to offer engineering services directly to the public
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