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svetlana [45]
2 years ago
14

Which pair of concepts are closely related?

Physics
2 answers:
Paha777 [63]2 years ago
8 0
I believe it’s c but I don’t really know but here is why gravity is also a part of friction or that is at least what I was told
OlgaM077 [116]2 years ago
7 0

Answer:

I believe it would be C. friction and gravity

Explanation:

They both deal with pulling/pushing objects.

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an average net force of 31.6 N is used to accelerate a 15.0 kg object uniformly from rest to 10.0 m/s leftward. What is the chan
pickupchik [31]

Answer:

-150 kg m/s

Explanation:

The change of momentum is calculated as ;

Δp= m*Δv where

where

Δp= change in momentum

Δv = vf-vi

m= mass of the object

Change in momentum is also calculated when using the formula;

Δp = F * Δt   when F is the net force applied and Δt is the time of action.

In this case;

m= 15 kg

vf=  -10 m/s

vi= 0 m/s

Taking rightward direction to be positive, then leftward will be negative.

Applying the formula as;

Δp = m*Δv

Δp = 15 * { -10 -0} = 15*-10 = -150 kg m/s

6 0
2 years ago
A ? watcher is a citizen who is paid by the parties to keep a watchful eye on the voters and the officials.
VARVARA [1.3K]
A poll watcher
<span>a person who is paid by the parties to  watch the voters and officials to make sure everything is fair</span>
6 0
3 years ago
Read 2 more answers
Two particles are traveling through space. At time t the first particle is at the point (−1 + t, 4 − t, −1 + 2t) and the second
Pie

Answer:

Yes, the paths of the two particles cross.

Location of path intersection = ( 1 , 2 , 3)

Explanation:

In order to find the point of intersection, we need to set both locations equal to one another. It should be noted however, that the time for each particle can vary as we are finding the point where the <u>paths</u> meet, not the point where the particles meet themselves.

So, we can name the time of the first particle T_F ,  and the time of the second particle T_S.

Setting the locations equal, we get the following equations to solve for T_F and T_S:

(-1 + T_F) = (-7 + 2T_S)                     Equation 1

(4 - T_F) = (-6 + 2T_S)                        Equation 2

(-1 + 2T_F) = (-1 + T_S)                     Equation 3

Solving these three equations simultaneously we get:

T_F = 2 seconds

T_S = 4 seconds

Since, we have an answer for when the trajectories cross, we know for a fact that they indeed do cross.

The point of crossing can be found by using the value of T_F or T_S in the location matrices. Doing this for the first particle we get:

Location of path intersection = ( -1 + 2 , 4 - 2 , -1 + 2(2) )

Location of path intersection = ( 1 , 2 , 3)

5 0
3 years ago
Tiny cell structure that carry out specific functions within the cell
RSB [31]

Answer:

Organelles

Explanation:

I learned this in science.

8 0
3 years ago
Two resistors R1 = 3 Ω and R2 = 6 Ω are connected in parallel. What is the net resistance in the circuit?​
gtnhenbr [62]

Answer:

"2Ω" is the net resistance in the circuit.

Explanation:

The given resistors are:

R1 = 3Ω

R2 = 6Ω

The net resistance will be:

⇒  \frac{1}{R_{net}} =\frac{1}{R_1} +\frac{1}{R_2}

On substituting the values, we get

⇒  \frac{1}{R_{net}} =\frac{1}{3} +\frac{1}{6}

On taking L.C.M, we get

⇒  \frac{1}{R_{net}} =\frac{2+1}{6}

⇒  \frac{1}{R_{net}} =\frac{3}{6}

⇒  \frac{1}{R_{net}} =\frac{1}{2}

On applying cross-multiplication, we get

⇒ R_{net}=2 \Omega

3 0
2 years ago
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