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nadya68 [22]
3 years ago
13

Indicate what type, or types, of reaction each of the following represents: (a) H2 O(g) + C(s) ⟶ CO(g) + H2 (g) (b) 2KClO3 (s) ⟶

2KCl(s) + 3O2 (g) (c) Al(OH)3 (aq) + 3HCl(aq) ⟶ AlCl3 (aq) + 3H2 O(l) (d) Pb(NO3 )2 (aq) + H2SO4 (aq) ⟶ PbSO4 (s) + 2HNO3 (aq)
Chemistry
1 answer:
lubasha [3.4K]3 years ago
6 0

Answer :

(a) This reaction is a type of single displacement reaction.

(b) This reaction is a type of decomposition reaction.

(c) This reaction is a type of double displacement reaction.

(d) This reaction is a type of double displacement reaction.

Explanation :

(a) H_2O(g)+C(s)\rightarrow CO(g)+H_2(g)

This reaction is a type of single displacement reaction. It is a type of reaction in which the more reactive metal displaces the least reactive metal from its solution.

(b) 2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)

This reaction is a type of decomposition reaction. It is a type of reaction in which a single larger compound decomposes to give two or more smaller molecules as a product.

(c) Al(OH)_3(aq)+3HCl(aq)\rightarrow AlCl_3(aq)+3H_2O(l)

This reaction is a type of double displacement reaction. It is a type of reaction in which the cation and the anion of the two reactant exchange their places to give two another compounds as a product.

(d) Pb(NO_3)_2(aq)+H_2SO_4(aq)\rightarrow PbSO_4(s)+2HNO_3(aq)

This reaction is a type of double displacement reaction. It is a type of reaction in which the cation and the anion of the two reactant exchange their places to give two another compounds as a product.

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What happens when magnesium reacts with dilute acid?
iogann1982 [59]

The magnesium dissolves to form magnesium chloride and hydrogen gas is released.

Mg  + 2HCl    -----> MgCl2  + H2(g).

5 0
3 years ago
Assume the weight of an average adult is 70. kg, and that 420. kJ of heat are evolved per mole of oxygen consumed as a result of
seraphim [82]

Answer:

The temperature difference of the body after 3 hours = 5.16 K

Explanation:

we know that the number of moles of O₂ inhaled are 0.02 mole/min⁻¹

                                   or, 1.2 mole.h⁻¹

The average heat evolved by the oxidation of foodstuffs is then:

⇒          Q avg =\frac{1.2 X 420 X 10^{3} }{70} = 7.2 kj.h⁻¹.Kg⁻¹

the heat produced after 3 h would be:

                 =    7.2 kj. h⁻¹.Kg⁻¹ x 3 h

                 = 21.6 kj. kg⁻¹

                 = 21.6 x 10³ j kg⁻¹

We know Qp = Cp x ΔT

Assume the heat capacity of the body is 4.18 J g⁻¹K⁻¹

⇒ ΔT = \frac{Qp}{Cp}

⇒ ΔT = \frac{(21.6 X 10^{3} j.kg^{-1} ) }{(4.18 j k^{-1}g^{-1})   X (1000g.kg^{-1} )}

⇒ ΔT = 5.16 K

6 0
3 years ago
The pKb of the base cyclohexamine, C6H11NH2, is 3.36. What is the pKa of the conjugate acid, C6H11NH3
bonufazy [111]

Answer:

10.64

Explanation:

Let's consider the basic reaction of cyclohexamine, C₆H₁₁NH₂.

C₆H₁₁NH₂(aq) + H₂O(l) ⇄ C₆H₁₁NH₃⁺(aq) + OH⁻     pKb = 3.36

C₆H₁₁NH₃⁺ is its conjugate acid, since it donates H⁺ to form C₆H₁₁NH₂. C₆H₁₁NH₃⁺ acid reaction is as follows:

C₆H₁₁NH₃⁺(aq) + H₂O(l) ⇄ C₆H₁₁NH₂(aq) + H₃O⁺(aq)   pKa

We can find the pKa of C₆H₁₁NH₃⁺ using the following expression.

pKa + pKb = 14.00

pKa = 14.00 - pKb = 14.00 - 3.36 = 10.64

6 0
4 years ago
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