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3 years ago

Silver: 55.0% Ag-107, 45,0% Ag-109

Chemistry

1 answer:

iogann1982 [59]3 years ago

6 0

Answer:

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Convert 355 km/s into m/ns.

xxTIMURxx [149]

Answer:

0.000355 meters/nanosecond (m/ns)

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2 years ago

Read 2 more answers

Kemmi Major does some experimental work on the combustion of sucrose: C12H22O11(s) 12 O2(g) → 12 CO2(g) 11 H2O(g) She burns a 0.

Pavlova-9 [17]

Answer: $5.81\times 10^6J/mol$

Explanation:

Heat of combustion is the amount of heat released when 1 mole of the compound is completely burnt in the presence of oxygen.

$C_{12}H_{22}O_{11}(s)+12O_2\rightarrow 12CO_2(g)+11H_2O(g)$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.05392g}{342g/mol}=1.577\times 10^{-4}moles$

Thus $1.577\times 10^{-4}moles$ of sucrose releases = 916.6 J of heat

1 mole of sucrose releases = $\frac{916.6}{1.577\times 10^{-4}}\times 1=5.81\times 10^6J$ of heat

Thus ∆H value for the combustion reaction is $5.81\times 10^6J/mol$

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3 years ago

What are the reactants to burning paper and the products

posledela

<span>CO2 (carbon) is the main product that results from burning paper. The paper is the reactant When paper burns in a fire, the reactants are mostly carbon (the main substance in the paper) and oxygen (from the air).Co2 If paper is loaded with CaCO3 such as cigarette paper, CaCO3 decompose in to CaO and CO2</span>

3 0

2 years ago

Which of the following type of radiation is represented by 0 over negative 1 e? A.alpha emission B.beta emission C.positron emis

Zolol [24]

The answer is B. beta emission. Alpha emission is a particle with 2 protons and 2 neutrons. Positron emission is represented by 0 over positive 1 e. Gamma rays is 0 over 0 γ.

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3 years ago

The correct lewis structure for COH2 contains how many covalent bonds?

VARVARA [1.3K]

Answer:

Four covalent bonds.

Explanation:

Hello,

In this case, given the attached picture in which you can find the Lewis dot structure for metanal (formaldehyde) we can see two C-H bonds and two C-O bonds via a double bond, thus, we can compute the type of each bond given the electronegativities of hydrogen, carbon and oxygen which are 2.1, 2.5 and 3.5 respectively:

$C-H=2.5-2.1=0.4\\C-O=3.5-2.5=1.0$

Thus, since both electronegativity difference are less 1.7 we infer that all of them are covalent, therefore, it has four covalent bonds, two C-H bonds and a double C-O bond.

Best regards-

8 0

3 years ago