When the molecule undergoes chlorination with Cl2 on heating, the hydrogen atom of the alkyl group is replaced by the chlorine atom and form chloroalkanes. The molecule X containes three types of alkyl halides, therefore three different types of chloroalkanes are formed by the replacement of hydrogem atom linked to these alkyl groups. Thus the three different types of chloroalkanes are formed - primary, secondary, and thertiary chloroalkane. Chlorination is not selective so a mixture pf products results. The products formed by the reaction of the molecule with Y with Cl2 are shown on the attached file.
Answer:
Animals would, instead of getting energy from the food that they eat like meat or plants, they would get their energy from the sun like plants do.
Explanation:
Because like what the paper says, Chloroplasts help with the photosynthesis, which is the process in which a plant gains its energy.
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PLEASE GIVE BRAINLIEST</em></h2>
If the Ka of HCN = 5.0 x 10^-10
Since
(Ka) (Ka) - 1 x 10^ -14
then
the Kb of its conjugate base (CN-) = 2.0 X 10^-5
since
pH + pOH = 14
when the pH = 10.00
then
the pOH = 4.00
& the OH-
would then equal 1.0 X 10^-4
NaCN as a base does a hydrolysis in water:
CN- & water --> HCN & OH-
notice that equal amounts of OH- & HCN are formed
Kb = [HCN] [OH-] / [CN-]
2.0 X 10^-5 = [1.0 X 10^-4] [1.0 X 10^-4] / [CN-]
[CN-] =(1.0 X 10^-8) / (2.0 X 10^-5)
[CN-] = (5.0 X 10^-4)
that's 0.00050 Molar
which is 0.00050 moles in each liter of aqueous KCN solution
which is
0.00025 moles KCN in 500. mL of aqueous KCN solution
use molar mass of KCN, to find grams:
(0.00025 moles KCN) (65.12 grams KCN / mole) = 0.01628 grams of KCn
which is 16.3 mg of KCN
& rounded to the 2 sig figs which are showing in the Ka of HCN , "5.0" X 10^-10
your answer would be
16 mg of KCN
sorry even after making a correction in calcs , I don't get one of your answers.
the only way that I could get one of them is to pretend that yours was a 1 sig fig problem,
in which case your 16 mg would round off to 20 mg.
but you have 3 sig figs in "500. ml", & 2 sig figs in both the "pH of 10.00."
& The Ka of HCN = "5.0 x 10^-10."
it does however take 12 mg of NaCN, to make 500. mL of aqueous solution pH of 10.00. the molar mass of NaCN has the smaller molar mass of 49.00 grams per mole.
maybe they meant NaCN, but wrote KCN instead.
I hope i answered this correctly for you.
Answer:
thanks
Explanation:
Mr motivational speaker for your concern
hi friend! its b, or a 1:2 ratio. i looked it up for help, and didn't have anything, so I did 1:2 and it was correct.
