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Svetradugi [14.3K]
3 years ago
9

Lewis structure for carbon tetrabromide (CBrÁ), in which a central carbon atom is bound to four atoms of the group 7A element br

omine?
Chemistry
1 answer:
nlexa [21]3 years ago
7 0
Remember that carbon has 4 electrons in its valence shell meanwhile bromine has 7

So i think the lewis structure would be :

Br

C       Br      Br  

Br

Hope this helps

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Trans-2-butene does not exhibit a signal in the double-bond region of the spectrum (1600–1850 cm−1); however, ir spectroscopy is
Elza [17]
However <em>trans</em>-2-Butene does not give a characteristic peak in 1620-1680 cm⁻¹ region but still the presence of carbon double bond carbon can be detected by detecting following peaks in IR Spectrum.

1)  3010-3100 cm⁻¹:
                               As in trans-2-Butene a hydrogen atoms ate attached to sp² hybridized carbon, therefore the stretching of =C-H (C-H) bond will give a peak of medium intensity in the range of 3010-3100 cm⁻¹.

2)  675-1000 cm⁻¹:
                             Another peak which is given by the bending of =C-H (C-H) bond with strong intensity will appear in the range of 675-1000 cm⁻¹.
3 0
3 years ago
How many moles of KNO3 are in 500 mL of 2. 0 M KNO3? mol KNO3.
8090 [49]

The moles can be defined as the mass of the substance with respect to molar mass. The moles of potassium nitrate is 1 mol.

<h3>How to calculate moles of a substance?</h3>

The moles of a compound can be calculated from:

\rm Moles=\dfrac{Mass}{Molar\;mass}

The molarity can be defined as the moles of solute in a liter of solution.

The molarity can be expressed as:

\rm Molarity=\dfrac{Moles\;\times\;1000}{Volume\;(mL)}

The molarity of potassium nitrate solution is 2 M, and the volume is 500 mL.

The moles of potassium nitrate is given as:

\rm 2\;M=\dfrac{Moles\;\times\;1000}{500\;mL}\\ Moles=\dfrac{2\;\times\;500}{1000}\;mol\\ Moles=1\;mol

The moles of potassium nitrate in 2 M, 500 mL solution are 1 mol.

Learn more about moles, here:

brainly.com/question/15209553

4 0
1 year ago
Determine the overall energy change for the reaction between hydrogen and oxygen shown in Question 13. Use Figure 2.
zimovet [89]

Answer:

–500KJ

Explanation:

Data obtained from the question include the following:

Heat of reactant (Hr) = 800KJ

Heat of product (Hp) = 300KJ

Enthalphy change (ΔH) =..?

The enthalphy change is simply defined as the difference between the heat of product and the heat of reactant i.e

Enthalphy change = Heat of product – Heat of reactant

ΔH = Hp – Hr

With the above formula, we can easily calculate the enthalphy change as follow

ΔH = Hp – Hr

ΔH = 300 – 800

ΔH = –500KJ.

Therefore, the overall energy change for the reaction between hydrogen and oxygen shown in the diagram above is –500KJ

5 0
3 years ago
Describe the region in model 1 where the highest concentration of hydrogen ion (h + ) is located
neonofarm [45]
<span>THE HIGHEST CONCENTRATION OF HYDROGEN IONS IS LOCATED IN THE INTER-MEMBRANE SPACE. HYDROGEN IONS REACH THE INTER-MEMBRANE SPACE THROUGH PROTEIN CHANNELS EMBEDDED IN THE MITOCHONDRIAL MEMBRANE. THE MAIN FUNCTION OF INTER MEMBRANEIS OXIDATIVE PHOSPHORLATON. ENERGY IS REQUIRED TO MOVE THE HYDROGEN IONS ACROSS THE MEMBRANE BECAUSE THE HYDROGEN IONS ARE MOVING AGAINST THE CONCENTRATION GRADIENT. H+ GOES AGAINST THE CONCENTRATION GRADIENT THE USE OF THE GRADIENT TO DRIVE ATP SYNTHASE. HYDOGEN IONS DRIVE ATP SYNTHASE IN PHTOSYNTHESIS. THIS HAPPENS WHEN HYDROGEN IONS GET PUSHED ACROSS THE MEMBRANE CREATING A HIGH CONCENTRATION INSIDE THE THYLAKOID.</span>
7 0
3 years ago
3. What is the mass % of a solution that contains 36g KCl in 475g of water?
stira [4]

Answer:

%KCl = 7.05%

%Water = 92.95%

Explanation:

Step 1: Given data

  • Mass of KCl (solute): 36 g
  • Mass of water (solvent): 475 g

Step 2: Calculate the mass of the solution

The mass of the solution is equal to the sum of the masses of the solute and the solvent.

m = 36 g + 475 g = 511 g

Step 3: Calculate the mass percentage of the solution

We will use the following expression.

%Component = mComponent/mSolution × 100%

%KCl = 36 g/511 g × 100% = 7.05%

%Water = 475 g/511 g × 100% = 92.95%

7 0
2 years ago
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