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Given Data: Diameter 'd' = 30 cm = 0.3 m Lifting Weight 'W' = mg = 2000*9.81 N = 19,620 N Calculations: Area of the lift 'A' = <span>pi\over4*d^2=pi\over4*0.3^2=0.07 m^2
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Answer:
The correct answer is:
(a) 84.240 kg
(b) 24.038 m
Explanation:
The given values are:
Force,
F = 81.0 N
Distance,
S = 13.0 m
Time,
t = 5.20 s
As we know,
The acceleration of mass will be:
⇒
On substituting the given values, we get
⇒
⇒
⇒
(a)
The mass of the block will be:
⇒
On substituting the given values, we get
⇒
⇒
(b)
The final velocity after a given time i.e.,
t = 5.00 s
⇒
On substituting the values, we get
⇒
⇒
In time, t = 5.00 s
The distance moved by the block will be:
⇒
On putting the values, we get
⇒
⇒
Answer:
The answer to your question is: B. F = 45 N
Explanation:
Newton's second law of motion states that the acceleration of an object is directly proportional to the force exerted and inversely proportional its mass.
Data
F = ?
a = 3 m/s²
m = 15 kg
Formula
F = ma
Process
F = ( 15)(3)
F = 45 N