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Flauer [41]
3 years ago
8

A 2000 kg car experiences a constant braking force

Physics
1 answer:
Marat540 [252]3 years ago
4 0
In that case, there are three possible scenarios:

-- If the braking force is less than the force delivered by the engine,
then the car will continue to accelerate, and the brakes will eventually
overheat and erupt in flame.

-- If the braking force is exactly equal to the force delivered by the engine,
then the car will continue moving at a constant speed, and the brakes will
eventually overheat and erupt in flame.

-- If the braking force is greater than the force delivered by the engine,
then the car will slow down and eventually stop.  If it stops soon enough,
then the absorption of kinetic energy by the brakes will end before the
brakes overheat and erupt in flame.  Even if the engine is still delivering
force, the brakes can be kept locked in order to keep the car stopped ...
They do not absorb and dissipate any energy when the car is motionless.
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What is hard but flexible structure is found in the nose and ears
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Explain why open pipes are preferred to closed pipe in the production of music-​
tatuchka [14]

Answer:

The frequencies of sounds made by these two types of instruments are different because of the different ways that air will move at a closed or open end of the pipe. Open pipes do not produce superior tone than closed (or stopped) pipes, therefore different types of pipes are used to produce different tonal qualities.

Explanation:

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3 years ago
the maximum normal force a pilot can withstand is about eight times his weight. What is the maximum radius of curvature that a j
neonofarm [45]

Complete Question

the maximum force a pilot can stand is about seven times his weight. what is the minimum radius of curvature that a jet plane's pilot, pulling out of a vertical dive, can tolerate at a speed of 250m/s?

Answer:

The value is    r = \frac{250^2 }{6 * 9.8 }

Explanation:

From the question we are told that

 The  weight of the pilot is   W =  mg

 The maximum force a pilot can withstand is  F_{max} =  7 W =  7 (mg)

 The speed is  v  =  250 \ m/s  

Generally the centripetal force acting on the pilot is equal to the net force acting on the pilot i.e

      F_c =  F_{max} - mg

Here N  is the normal force acting on the pilot

Now

      F_c =  \frac{m v^2 }{r}

So

      \frac{m v^2 }{r} =  7(mg)  - mg  

=>  r = \frac{v^2 }{6g}

=>  r = \frac{250^2 }{6 * 9.8 }

=>  r =  1063 \  m

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3 years ago
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