The acceleration of the car is 0.5 meters per seconds square.
Given the following data:
- Initial velocity, U = 30 m/s
Note: The final velocity (V) of the car would be zero (0) m/s when it comes to a stop.
To find the acceleration of the car, we would use the third equation of motion;
Mathematically, the third equation of motion is given by the formula;
<em>Acceleration, a </em><em>=</em><em> 0.5 </em>
<em></em>
Therefore, the acceleration of the car is 0.5 meters per seconds square.
Read more: brainly.com/question/8898885
Which energy is best discribed for you and math
Answer:
F=480.491 N
Explanation:
Given that
mass ,m = 22 kg
Angular speed ω = 40 rev/min
ω =4.18 rad/s
The radius r= 1.25 m
We know that centripetal force is given as
F=m ω² r
Now by putting the values in the above equation we get
F=480.491 N
Therefore the centripetal force on the child will be 480.491 N.
a) We use the formula:
T = [g sinθ – a] * m
where g is gravity, θ is the angle, a is acceleration, m is mass
T = [9.81 sin37 - 2.00] * 12 = 46.85 N <span>
b) We use the formula for moment of interia:</span>
I = T * r² / a
I = 46.85 * 0.10² / 2.00 = .2343 kg∙m² <span>
c) The formula we can use here is:</span>
w = α * t = (a/r) * t
w = (2/.10) * 2
<span>w = 40 rad/sec</span>
Battery, a wire and the nergy source.
