That could be a symptom but I recommend going to your doctor just to be on the safe side!
The change in the total energy of the object is zero (0).
The given parameters:
work done by the machine, W = 50 J
mass of the object, m = 10 kg
To find:
the change in the total energy of the object
The change in the total energy of the object is the difference between the objects initial energy due to its position and the work done on the object.
Based on work energy-theory, the work done on the object is equal to the energy of the object.
- The energy of the object = work-done on the object
- The change in total energy = 50 J - 50 J = 0
Thus, the change in the total energy of the object is zero (0).
Learn more here: brainly.com/question/20377140
Answer:
Explanation:
Mass = 624 gm = .624 kg
weight = .624 x 9.8
= 6.11 N
Radius of ball = 12.15 x 10⁻² cm
volume of ball
= 4/3 x 3.14 x ( 12.15 x 10⁻²)³
= 7509.26 x 10⁻⁶ m³
Buoyant force = weight of displaced water
= 7509.26 x 10⁻⁶ x 10³ x 9.8
= 73.59 N
b ) Since buoyant force exceeds the weight of the ball , it will float .
c )
Let volume v sticks out while floating .
Volume under water
= 7509.26 x 10⁻⁶ - v
its weight
= (7509.26 x 10⁻⁶ - v ) x 10³ x 9.8
For floating
(7509.26 x 10⁻⁶ - v ) x 10³ x 9.8 = .624 x 9.8 ( weight of ball )
(7509.26 x 10⁻⁶ - v ) x 10³ = .624
7.509 - v x 10³ = .624
v x 10³ = 7.509 - .624
v x 10³ = 6.885
v = 6.885 x 10⁻³ m³
fraction
= v / total volume
= 6.885 x 10⁻³ / 7.51 x 10⁻³
91.67 %
V=IR
Potential Difference (v)= Current (A) * Resistance (Ω)
As V increases, R also increases.