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gizmo_the_mogwai [7]
4 years ago
10

Deltas, like this one, are formed at the mouth of a river. They are formed by the ___________ of sediments, soil, sand, gravel,

which is a constructive process.
Physics
2 answers:
adelina 88 [10]4 years ago
7 0
Compression is the correct answer
vitfil [10]4 years ago
3 0

Deltas, like this one, are formed at the mouth of a river. They are formed by the.     Of  sentiments soil sand gravel which is a constructive process.

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The position of the earth and moon.

Explanation:

The position of the earth and moon are the two main factors.

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Due to radiation and absorption, what is the maximum flame temperature in a fire?
ludmilkaskok [199]

The maximum flame temperature in a fire is 1500-1600K due to radiation and absorption.

<h3>What do you mean by radiation and absorption?</h3>

In physics, matter (usually electrons bound in atoms) absorbs electromagnetic radiation in order to convert the energy of a photon into the internal energy of the absorber (for example, thermal energy). Attenuation, or the steady decrease in light wave intensity as it travels through a medium, is a prominent effect. In some circumstances (optics), the medium's transparency changes by a factor that varies as a function of wave intensity, leading to saturable absorption (or nonlinear absorption), even though the absorption of waves typically does not depend on their intensity (linear absorption).

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1 year ago
Plz help I’ll give Brainliest
Mariana [72]

Answer:

c

Explanation:

5 0
3 years ago
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Fossils found in the La Brea tar pits indicate a California climate that was A) similar to today's climate. B) similar to the pr
NikAS [45]

Answer:

i believe it is D but not 100% sure

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At a depth of 1030 m in Lake Baikal (a fresh water lake in Siberia), the pressure has increased by 100 atmospheres (to about 107
dangina [55]

Answer:

A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.

Explanation:

The bulk modulus is represented by the following differential equation:

K = - V\cdot \frac{dP}{dV}

Where:

K - Bulk module, measured in pascals.

V - Sample volume, measured in cubic meters.

P - Local pressure, measured in pascals.

Now, let suppose that bulk remains constant, so that differential equation can be reduced into a first-order linear non-homogeneous differential equation with separable variables:

-\frac{K \,dV}{V} = dP

This resultant expression is solved by definite integration and algebraic handling:

-K\int\limits^{V_{f}}_{V_{o}} {\frac{dV}{V} } = \int\limits^{P_{f}}_{P_{o}}\, dP

-K\cdot \ln \left |\frac{V_{f}}{V_{o}} \right| = P_{f} - P_{o}

\ln \left| \frac{V_{f}}{V_{o}} \right| = \frac{P_{o}-P_{f}}{K}

\frac{V_{f}}{V_{o}} = e^{\frac{P_{o}-P_{f}}{K} }

The final volume is predicted by:

V_{f} = V_{o}\cdot e^{\frac{P_{o}-P_{f}}{K} }

If V_{o} = 1\,m^{3}, P_{o} - P_{f} = -10132500\,Pa and K = 2.3\times 10^{9}\,Pa, then:

V_{f} = (1\,m^{3}) \cdot e^{\frac{-10.1325\times 10^{6}\,Pa}{2.3 \times 10^{9}\,Pa} }

V_{f} \approx 0.996\,m^{3}

Change in volume due to increasure on pressure is:

\Delta V = V_{o} - V_{f}

\Delta V = 1\,m^{3} - 0.996\,m^{3}

\Delta V = 0.004\,m^{3}

A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.

8 0
3 years ago
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