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Llana [10]
2 years ago
12

The figure(Figure 1) shows the angular-velocity-versus-time graph for a particle moving in a circle, starting from θ0=0 rad at t

=0s. Draw the angular-position-versus-time graph. Include an appropriate scale on both axes.

Physics
1 answer:
Anon25 [30]2 years ago
8 0

Answer:

As position is the product of velocity and time, the area under the velocity-time curve will be the position.

Between 2 and 4 s, the area increases linearly to 20(4) = 80

Between 4 and 6 s, the additional area is 0(2) = 0

Between 6 and 8 s the area increases linearly by -10(2) = -20

which is a decrease.

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Answer:

Explanation:

The answer is Climate

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2 years ago
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A damped harmonic oscillator consists of a mass on a spring, with a small damping force that is proportional to the speed of the
exis [7]

Answer:

2.19 N/m

Explanation:

A damped harmonic oscillator is formed by a mass in the spring, and it does a harmonic simple movement. The period of it is the time that it does one cycle, and it can be calculated by:

T = 2π√(m/K)

Where T is the period, m is the mass (in kg), and K is the damping constant. So:

2.4 = 2π√(0.320/K)

√(0.320/K) = 2.4/2π

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(√(0.320/K))² = (0.38197)²

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3 years ago
What is the energy in joules of a mole of photons associated with visible light of wavelength 486 nm?
ivann1987 [24]

Answer:

2.46\cdot 10^5 J

Explanation:

The energy of a single photon is given by:

E=\frac{hc}{\lambda}

where

h is the Planck constant

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For the photon in this problem,

\lambda=486 nm=4.86\cdot 10^{-7}m

So, its energy is

E_1=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.86\cdot 10^{-7}m}=4.09\cdot 10^{-19} J

One mole of photons contains a number of photons equal to Avogadro number:

N_A = 6.022\cdot 10^{23}

So, the total energy of one mole of photons is

E=N_A E_1 = (6.022\cdot 10^{23})(4.09\cdot 10^{-19} J)=2.46\cdot 10^5 J

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3 years ago
how many times does the kinectic energy of a car increase when traveling 60 mph as opposed to traveling 30 mph
Bumek [7]
The car at 60 kph has 9 times more kinetic energy than the car traveling at 20 kph. This assumes that both cars have the same mass. Kinetic energy depends on the square of thee speed so if one car is going 3 times faster, its kinetic energy will be 3^2 ( = 9 ) greater. The car going at 60 kph will have 4 times the KE of the car going at 30 kph ( again assuming that the cars have the same mass.)
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What is the acceleration of the box?
worty [1.4K]

Answer:

a=4,32m/s^2

Explanation:

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