Question

The figure(Figure 1) shows the angular-velocity-versus-time graph for a particle moving in a circle, starting from θ0=0 rad at t=0s. Draw the angular-position-versus-time graph. Include an appropriate scale on both axes.

Answer 1

Answer:

As position is the product of velocity and time, the area under the velocity-time curve will be the position.

Between 2 and 4 s, the area increases linearly to 20(4) = 80

Between 4 and 6 s, the additional area is 0(2) = 0

Between 6 and 8 s the area increases linearly by -10(2) = -20

which is a decrease.