The figure(Figure 1) shows the angular-velocity-versus-time graph for a particle moving in a circle, starting from θ0=0 rad at t
=0s. Draw the angular-position-versus-time graph. Include an appropriate scale on both axes.
1 answer:
Answer:
As position is the product of velocity and time, the area under the velocity-time curve will be the position.
Between 2 and 4 s, the area increases linearly to 20(4) = 80
Between 4 and 6 s, the additional area is 0(2) = 0
Between 6 and 8 s the area increases linearly by -10(2) = -20
which is a decrease.
You might be interested in
Answer:
404.4 m
Explanation:
Converting the initial speed from km/h to m/s then
The acceleration is resolved as shown in the figure hence
deceleration of the truck along the inclined plane will be
where g is acceleration due to gravity
Substituting g with then
Using kinematic equation
and making s the subject then
where v and u are final and initial velocities respectively
Substituting 0 for v, 38.89 m/s for u and then
