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Katarina [22]
3 years ago
14

A 2.0-kg block is on a perfectly smooth (frictionless) ramp that makes an angle of 30^\circ30 ​∘ ​​ with the horizontal. What is

the force of the ramp on the block?

Physics
1 answer:
Nastasia [14]3 years ago
7 0

Answer:

Explanation:

Since the surface is frictionless therefore there will be no friction force on block but there will be weight of block which we can divide in to two components i.e. mgcosθ &mgsinθ which is perpendicular and parallel to the surface respectively.

In response to mgcosθ ramp will apply a normal force to the block which will be of equal magnitude to that of mgcosθ.

Therefore Ramp will apply a Force of mgcosθ on block where m is the mass of block.

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Answer:

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Explanation:

Given the data in the question;

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at what distance from the explosion is the sound intensity half this value?

we know that;

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Now, let r² be the distance where sound intensity is half, i.e I₂ = I₁/2

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r₂² = 54450

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Therefore, required distance is 233.35 m

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