A 2.0-kg block is on a perfectly smooth (frictionless) ramp that makes an angle of 30^\circ30 ∘ with the horizontal. What is
the force of the ramp on the block?
1 answer:
Answer:
Explanation:
Since the surface is frictionless therefore there will be no friction force on block but there will be weight of block which we can divide in to two components i.e. mgcosθ &mgsinθ which is perpendicular and parallel to the surface respectively.
In response to mgcosθ ramp will apply a normal force to the block which will be of equal magnitude to that of mgcosθ.
Therefore Ramp will apply a Force of mgcosθ on block where m is the mass of block.
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Answer:
The sponge must go deep
Explanation:
If F = 6360 N, then it is required to find how deep can an object with this force hitting on a sponge get.
We know that, F = mgh
m is mass
g is acceleration due to gravity
So, the sponge must go deep.