Answer:
the correct answer is option C which is 50 units.
Explanation:
given,
two vector of magnitude = 30 units and of 70 units
to calculate resultants vector = \sqrt{a^2+b^2+2 a b cos\theta}
cos θ value varies from -1 to 1
so, resultant vector
=
a = 30 units and b = 70 units
=
= 40 units to 100 units
hence, the correct answer is option C which is 50 units.
Answer:
The value of g = 0.6168 m/s².
Explanation:
Given that,
On a planet X,
Length of the pendulum(L) = 0.25 meters,
Time period of the pendulum(T) = 4 seconds.
We have to find the 'g' value on the planet.
The 'g' value on a planet can be found by a pendulum with help of the formula,
T = 2π ×
From this, g = 4π² ×
Using the above formula and substituting the values,we get,
g = 0.6168 m/s².
Answer:
36,000j
Explanation:
W= P•t
120•300= 36000
I checked my answer with P= W/t and got the right answer
hope this helps
Answer:
The power dissipated by the meter is 1188W
Explanation:
Here we have a circuit constituted with a power source and two resistors in series, we can calculate the power dissipated by the meter using the following formula:
We first need to fin the current going through the circuit:
because they are connected in series. So: