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Anna71 [15]
3 years ago
8

How do I solve a multiplication table

Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer:

1. Relate multiplication to addition. Avoid starting with memorization. Students typically struggle to memorize multiplication facts on the first ...

2. Start with the multiples of zero and one.

3. Cover the multiplication table, starting with the “easy” numbers.

4. Show how the commutative property makes things easier.

5. Break memorization down into easy steps.

Step-by-step explanation:

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olga2289 [7]
The width is 16 so the length is 64  (TO clarify W=16)

Hope this helps :)
7 0
3 years ago
Read 2 more answers
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MatroZZZ [7]
Hello There
Its pretty tricky but here is your answer
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<span>4833.97738

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5 0
3 years ago
Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located
arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}&#10;\\\\&#10;c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\&#10;-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}&#10;\\\\\\&#10;csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

3 0
3 years ago
45.6/109.2 = x/115<br><br> Is x, 48.02?
MAXImum [283]
Yes correct x is 48.02 here is why.

simplify 45.6/109.2 to 0.417582

multiply both sides by 115

simplify 0.417582 x 115 to 48.021978

switch sides

Answer: x = 48.021978
4 0
3 years ago
Help with 9 and 10 please?
JulsSmile [24]
9. Let x equal the number

Two less than a number is

x - 2

Is more than 15 is

> 15

Put them together for

x-2 > 15

Now solve

x-2 > 15
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10. Let x equal a number

Seven more than a number is

x+ 7

Is less than or equal to 27 is

<= 27

Put them together for

x + 7 <= 27

Now solve

x+ 7 <= 27
x <= 20
3 0
3 years ago
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