The alcoholic can seek rehab
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Answer: In an experiment, mice were fed glucose (C6H12O6) containing a small amount of radioactive carbon. The mice were closely monitored, and in a few minutes, radioactive carbon atoms showed up in _Carbon dioxide/Carbon IV oxide (CO2)_
Explanation: The end product of Glucose at the end of metabolism is Carbon dioxide, water and ATP.
C6H12O6 + 6O2 ----------> 6CO2 + 6H2O + ATP (Energy)
The carbon is converted to Carbon dioxide. So, the radioactive Carbon appears in the Carbon dioxide/Carbon IV oxide (CO2).
Answer:
100mL of 0.10M HNO2 and 0.10M NaNO2
Explanation:
because solution has the greatest buffering capacity when the concentration of the weak acid is = at the concentration of its conjugate base.