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Oliga [24]
3 years ago
9

Which of the following is the correct name for Cr203?

Chemistry
2 answers:
nikitadnepr [17]3 years ago
6 0

Answer:

The correct name is Chromium(iii) oxide

algol133 years ago
4 0
It’s B. Chromium(III) oxide
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How many grams of H2 are needed to produce 13.33g of NH3?
Zanzabum

The reaction to form NH3 is : N2 + 3H2-> 2NH3 12,33g NH3 is 12,33/17,03=0,3 =0,724 moles of NH3 moles NH3. So you need 1,5*0,724 = 1,086 moles H2 1,086*2,016 = 2,189 g of H2 is needed ro form 12,33 g NH3

3 0
3 years ago
The 3 components of air
jok3333 [9.3K]

Nitrogen (around 78%), Oxygen (around 21%), and Argon (around 1%).

Hope this helps :)

8 0
2 years ago
Read 2 more answers
A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

3 0
2 years ago
Calculate the mass, in grams, of 1.2000 mol Mg₃N₂
fredd [130]
So what do you want me to do
Explanation
7 0
2 years ago
Convert 23.92inHg to torr.
White raven [17]
<h3><u>Answer;</u> </h3>

= 607.568 Torr

<h3><u>Explanation; </u></h3>

1 in of mercury is equivalent to 25.4 Torr  

Therefore;

23.92 InHg will be equal to;

23.92 × 25.4  

<u>= 607.568 Torr</u>

7 0
3 years ago
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