Which of the following is the correct name for Cr203?
2 answers:
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Answer : The molar mass of the solute will be 87.90 g/mol.
Explanation : We know the formula for elevation in boiling point, which is
Δt = i
m
given that, Δt = 0.357, = 5.02 and mass of 
= 40,
on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X
.
Now, 0.250/ 2.844 X = 87.90 g/mol. which is the weight of unknown component.
Explanation : We know the formula for elevation in boiling point, which is
Δt = i
given that, Δt = 0.357,
on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X
Now, 0.250/ 2.844 X
<u>Answer:</u>
3.67 moles
<u>Step-by-step explanation:</u>
We need to find out the number of moles present in 350 grams of a compound.
Molar mass of = 24.305
Molar mass of = 35.453
So, one mole of = 24.305 + (35.453 * 2) = 95.211g
1 Mole in 1 molecule of =
Therefore, number of moles in 350 grams of compound = 0.0105 * 350
= 3.67 moles