A train is travelling at 15m/s. It accelerates at 3m/s² for 20 seconds. How far does the train travel in this time?

If the real gi tract is 9 meters long, the model you created is what fraction of the real one

Sedbober [7]

Answer:

a

Explanation:

a

7 0

4 years ago

Suppose you display a 1 kHz, 2 V sine wave in channel A and a DC, 1V signal in channel B with sensitivities set on 1V/div. You s

defon

Answer:

You are going to see the AC functions shifted down

Explanation:

Because you had a positive DC signal first, you had to readjust the position to the middle, otherwise, the sum of AC and DC would have been shifted up; because of this, your cursor has been moved down and ones the DC disappears from channel B the signal will be shifted down.

Note: Changing from DC to AC in channel B will kill all the DC signal

5 0

3 years ago

A water trough is 12 feet long, and its cross section is an equilateral triangle with sides 2 feet long. Water is pumped into th

MAXImum [283]

Answer:

The water level rises at 11.76 $ft^{2} /s$

$h=\sqrt{3/2} s$ let be h: height and s: side of an equilateral triangle

Explanation:

The picture shows a diagram of the situation, first we have to determine the height of the trough as follows:

With the Pytagorean Theorem we can find out that:

$h^{2} =s^{2} -s^{2} /4 =\sqrt{3} /2 s$

Then, the area of an equilateral triangle, as any triangle, is a half of its base times its height:

$A=\frac{1}{2} hs=\frac{1}{2} \frac{\sqrt{3} }{2} s^{2} =\frac{\sqrt{3} }{4} s^{2}$

Replacing values, we have:

$A=1.73ft^{2}$

That is the total area of the trough, but the problem specifies that it has been filled until 0.5 ft. Therefore, we have to find the cross section area of the water flow by substracting the total area minus the unfilled area of the trough:

$h_{u}: height of the unfilled triangle\\s_{u} : side of the unfilled triangle\\A_{u}: area of the unfilled triangle\\h_{u}=\sqrt{3} -0.5 =1.23\\s_{u}= \frac{2}{\sqrt{3} } 1.23=1.42\\A_{u}=\frac{\sqrt{3} }{4} 1.42^{2} =0.87ft^{2} A_{u}$

Then, the cross section area of water flow is

$A_{s} =1.73ft^{2} -0.87ft^{2} =0.85ft^{2}$

Finally, to determine the speed of water flow at this point we solve for v, the flow formula:

$Q: water flow\\v: speed\\Q=vA\\v=Q/A =\frac{10ft^{3}/s }{0.85ft^{2} } =11.76 \frac{ft^{2}}{s}$

6 0

3 years ago

Which of these best describes a situation where science is used?

JulijaS [17]

Predicting weather by looking at clouds. Because you are predicting which relates to the scientific method

3 0

3 years ago

Read 2 more answers

Looking at this barometer, is the air pressure high or low? What type of weather can be predicted?

ASHA 777 [7]

It really depends on the altitude of the barometer.

-- If the picture was taken in Denver, Colorado, where the long-term
average atmospheric pressure is around 24.5", then this barometer
is showing slightly higher than normal, and good weather can be
predicted.

-- If the picture was taken anywhere along the east coast of the US,
where standard "sea level" pressure is 29.92", then this barometer
is reading alarmingly low ! There's either a hurricane in progress
right now, or one can be predicted to arrive very soon and you'd best
pick up your barometer and head inland as fast as you can.

3 0

3 years ago

Read 2 more answers