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RoseWind [281]
3 years ago
8

What is the net ionic equation for AgNO3 (aq) + K2SO4 (aq)

Chemistry
1 answer:
lesya [120]3 years ago
4 0
2Ag +(aq) + SO4 2-(aq)----->Ag2SO4 (s)
You might be interested in
Theoretical yield and percentage yield of:
dem82 [27]

Answer:

Theoretical yield of potassium nitrate = 1.21 g

Theoretical yield of lead iodide = 2.77 g

Explanation:

Given data:

Mass of Lead nitrate = 2.00 g

Mass of potassium iodide = 3.00 g

Theoretical yield = ?

Percent yield = ?

Solution:

Chemical equation:

Pb(NO₃)₂  +  2KI   →  PbI₂ + 2KNO₃

Now we will calculate the number of moles of lead nitrate.

Number of moles = mass/ molar mass

Number of moles = 2.00 g/ 331.2 g/mol

Number of moles = 0.006 mol

Number of moles of KI:

Number of moles = mass/ molar mass

Number of moles = 3.00 g/ 166 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of lead nitrate with potassium iodide with lead iodide and potassium nitrate.

                         Pb(NO₃)₂          :           PbI₂

                              1                   :             1

                           0.006             :           0.006

                       Pb(NO₃)₂            :           KNO₃

                              1                   :             2

                           0.006             :           0.006×2 =0.012

                            KI                   :           PbI₂

                              2                   :             1

                           0.02                :           1/2×0.02 = 0.01

                            KI                   :           KNO₃

                              2                  :             2

                           0.02               :            0.02

Theoretical yield of both product depend upon lead nitrate because it is limiting reactant.            

Theoretical yield of potassium nitrate:

Mass = number of moles × molar mass

Mass =  0.012 mol × 101.1 g/mol

Mass = 1.21 g

Theoretical yield of lead iodide:

Mass = number of moles × molar mass

Mass =  0.006 mol × 461.01 g/mol

Mass = 2.77 g

Percentage yield can not be determine because actual yield is not given.

7 0
3 years ago
NOT A SERIOUS QUESTION IM JUST EXPLORING BRAINLY.COM!!
vlabodo [156]

Well it matters If it touch with liquid or soild, if touched with liquid it is not call wet, but with soild yes because something dry will get went when touched with water but something wet will stay wet when touched with water.

8 0
3 years ago
I need help please ASAP
Yuliya22 [10]

Answer:

the name for NO is nitrogen monoxide

6 0
3 years ago
Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the pr
yuradex [85]

Explanation:

According the equation of Gibb's free energy -

∆G = ∆H -T∆S

∆G = is the change in gibb's free energy

∆H = is the change in enthalpy

T = temperature

∆S = is the change in entropy .

And , the sign of the  ΔG , determines whether the reaction is Spontaneous or non Spontaneous or at equilibrium ,

i.e. ,

if

• ΔG < 0 , the reaction is Spontaneous

• ΔG > 0 , the reaction is non Spontaneous

• ΔG = 0 , the reaction is at equilibrium

a.

N₂(g) + H₂(g)  → N₂H₄ (g)   ; ΔG⁰f = 159.3 kJ/mol

ΔG > 0 , the reaction is non Spontaneous  , the reaction is not feasible in the forward direction

b.

2Na(s) + O₂(g) → Na₂O₂ (s)   ; ΔG⁰ f = − 447.7kJ/mol

ΔG < 0 , the reaction is Spontaneous  , the reaction is feasible in the forward direction .

c.

C(s) + 2S(s)  →  CS₂ (g)   ; ΔG⁰f = 67.1 kJ/mol

ΔG > 0 , the reaction is non Spontaneous  , the reaction is not feasible in the forward direction

d.

Ca(s) + 12 O₂ (g) → CaO (s) ;  ΔG⁰f = −604.0 kJ/mol

ΔG < 0 , the reaction is Spontaneous  , the reaction is feasible in the forward direction .

8 0
4 years ago
The methylene chloride solution is filtered through sodium sulfate to:
Vlad [161]

Answer:

C. Dry the methylene chloride by removing water

Explanation:

Anhydrous sodium sulfate is known for its high capacity to absorb water, for this reason it is widely used in laboratories as a drying agent.

Sodium sulfate is a neutral molecule so it cannot be used to neutralize and is very stable, so it is difficult to precipitate organic molecules.

5 0
3 years ago
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