0.06105 moles is the number of moles of water lost.
<h3>What is molar mass?</h3>
Molar mass is defined as the mass in grams of one mole of a substance.
Given data:
Mass of water = 1.1g
Molar mass water = 18.016 g/mol
Moles of water =?
These quantities are related by the following equation;
Moles = 
Substituting the values of the quantities and solving for moles, we have;
Moles = 
= 0.06105 moles.
Hence, the 0.06105 moles is the number of moles of water lost.
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Ba(OH)₂(aq) + 2HNO₃(aq) = Ba(NO₃)₂(aq) + 2H₂O(l)
At the reaction of barium hydroxide with nitric acid there are no visual changes.
Ba(OH)₂(aq) + H₂SO₄(aq) = BaSO₄(s) + 2H₂O
At the reaction of barium hydroxide with sulfuric acid the precipitat of white color is formed.
Answer: Option (1) is the correct answer.
Explanation:
Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.
With increase in atomic size of the atom, there will be less force of attraction between the nucleus and the valence electrons of the atom. Hence, with lesser amount of energy the valence electrons can be removed.
When we move across a period then due to increase in force of attraction the size of atom decreases.
Thus, we can conclude that Phosphorus has a higher ionization energy than silicon because the outer orbitals of phosphorus are located closer to the nucleus than the outer orbitals of silicon.
Answer:
An acidic solution has a high concentration of hydrogen ions (H +start superscript, plus, end superscript), greater than that of pure water.
A buffer is usually composed of either:
- a weak base combined with its conjugate acid, or
- a weak acid combined with its conjugate base
Now, examining each of the choices:
1- KOH and NH3: since they are both bases, thus this mixture is not a buffer
2- HBr and NaCl: since HBr is a strong acid while NaCl is the salt of another different acid, thus this mixture is not a buffer
3- HCl and HBr: these are both considered to be strong acid, thus this mixture is not a buffer
4- HCHO2 and NaCHO2: as for HCH02, it is considered a weak base while NaCHO2 is considered its conjugate base, thus this mixture is a buffer
