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Doss [256]
3 years ago
14

A chemical reaction was used to separate a sample into its components. What conclusion about the sample can be formed based on t

he technique used?
A: It was a pure substance
B: It was a compound
C: It was a heterogeneous mixture
D: It was a homogeneous mixture
Chemistry
2 answers:
masya89 [10]3 years ago
6 0

Answer:

B: It was a compound

Explanation:

If a chemical reaction was used to separate a sample into its components,  then it was a compound. For example, water (H2O, a compound) can be separated by electrolysis into oxygen and hydrogen (its components). the chemical reaction is:

2 H2O -> O2 + 2 H2

Heterogeneous and homogeneous mixtures can be separated by physical ways. Pure substance can be either a compound or an element, so this option is not specific enough to be the correct answer.

Dvinal [7]3 years ago
3 0
C, a compound because it means it was made up of more than one element but, still able to be separated from the other compound(s)
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Is zn2+ a transition metal?​
4vir4ik [10]

Answer:

Yes.

Explanation:

Zn2+ is the zinc ion in aqueous solution.

Zinc is a transition metal.

These metals are in the middle of the periodic table and have similar properties.

7 0
3 years ago
A compound is formed when 171.2 g of carbon reacts with 28.8 g of hydrogen. What is the mass percent of hydrogen in the compound
IgorLugansk [536]
Following the law of conservation of mass, the mass percent of hydrogen in the resulting compound is 14.4%(wt/wt). This is assuming that all of the carbon reacts with all of the hydrogen. The solution is as follows:

mass % = mass hydrogen*100/total mass = 28.8*100/(28.8+171.2) = 14.4%
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3 years ago
What is the correct formula for calcium sulfate dihydrate?
Murljashka [212]

Answer:

It is CaSO4.2H2O

Explanation:

<em>C</em><em>a</em><em>l</em><em>c</em><em>i</em><em>u</em><em>m</em><em> </em><em>h</em><em>a</em><em>s</em><em> </em><em>a</em><em> </em><em>v</em><em>a</em><em>l</em><em>e</em><em>n</em><em>c</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>2</em><em> </em><em>b</em><em>e</em><em>c</em><em>a</em><em>u</em><em>s</em><em>e</em><em> </em><em>i</em><em>t</em><em> </em><em>h</em><em>a</em><em>s</em><em> </em><em>o</em><em>n</em><em>l</em><em>y</em><em> </em><em>t</em><em>w</em><em>o</em><em> </em><em>v</em><em>a</em><em>l</em><em>e</em><em>n</em><em>c</em><em>y</em><em> </em><em>e</em><em>l</em><em>e</em><em>c</em><em>t</em><em>r</em><em>o</em><em>n</em><em>s</em><em>.</em>

<em> </em><em>S</em><em>u</em><em>l</em><em>p</em><em>h</em><em>a</em><em>t</em><em>e</em><em> </em><em>(</em><em> </em><em>S</em><em>O</em><em>4</em><em>)</em><em>^</em><em>2</em><em>-</em><em> </em><em>i</em><em>s</em><em> </em><em>a</em><em> </em><em>r</em><em>a</em><em>d</em><em>i</em><em>c</em><em>a</em><em>l</em><em> </em><em>w</em><em>i</em><em>t</em><em>h</em><em> </em><em>a</em><em> </em><em>v</em><em>a</em><em>l</em><em>e</em><em>n</em><em>c</em><em>e</em><em> </em><em>v</em><em>a</em><em>l</em><em>u</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>2</em><em>.</em>

<em> </em><em> </em><em>W</em><em>h</em><em>e</em><em>n</em><em> </em><em>C</em><em>a</em><em>l</em><em>c</em><em>i</em><em>u</em><em>m</em><em> </em><em>c</em><em>o</em><em>m</em><em>b</em><em>i</em><em>n</em><em>e</em><em>s</em><em> </em><em>w</em><em>i</em><em>t</em><em>h</em><em> </em><em>s</em><em>u</em><em>l</em><em>p</em><em>h</em><em>a</em><em>t</em><em>e</em><em> </em><em>i</em><em>n</em><em> </em><em>b</em><em>o</em><em>n</em><em>d</em><em>i</em><em>n</em><em>g</em><em>,</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>F</em><em>o</em><em>r</em><em>m</em><em>u</em><em>l</em><em>a</em><em>r</em><em> </em><em>=</em><em>=</em><em>></em><em> </em> Ca<u>2</u><u>(</u>SO4)<u>2</u>

<em>B</em><em>u</em><em>t</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>2</em><em> </em><em>c</em><em>a</em><em>n</em><em>c</em><em>e</em><em>l</em><em> </em><em>out</em><em>.</em>

<em>O</em><em>v</em><em>e</em><em>r</em><em>a</em><em>l</em><em>l</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em>u</em><em>l</em><em>a</em><em>r</em><em>=</em><em>=</em><em>></em><em> </em>CaSO4

For hydrated, ==> CaSO4.H2O

3 0
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dangina [55]
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Read 2 more answers
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MAXImum [283]

Answer:

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2 years ago
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