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3 years ago

How is the name of each element in the periodic table represented?

Chemistry

2 answers:

Over [174]3 years ago

7 0

Answer:

A. One or two letters are used to represent the name of each element

APEX

Veseljchak [2.6K]3 years ago

5 0

Answer:

Explanation:

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what volume will it occupied 40 degrees celsius a gas sample was collected when a temperature is 27 degrees celsius and the volu

love history [14]

T_1=27°C
T_2=40°C
V_1=1L
V_2=?

Using Charles law

$\boxed{\sf \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}$

$\\ \sf\longmapsto V_1T_2=V_2T_1$

$\\ \sf\longmapsto 1(40)=27V_2$

$\\ \sf\longmapsto V_2=\dfrac{40}{27}$

$\\ \sf\longmapsto V_2=1.48\ell$

7 0

3 years ago

The mole fraction of CO2 in a certain solution with H2O as the solvent is 3.6 × 10−4. What is the approximate molality of CO2 in

nataly862011 [7]

Answer: C) 0.020 m

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molality=\frac{n\times 1000}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in g

Mole fraction of $CO_2$ is = $3.6\times 10^{-4}$ i.e. $3.6\times 10^{-4}$ moles of $CO_2$ is present in 1 mole of solution.

Moles of solute $(CO_2)$ = $3.6\times 10^{-4}$

moles of solvent (water) = 1 - $3.6\times 10^{-4}$ = 0.99

weight of solvent = $moles\times {\text {Molar mass}}=0.99\times 18=17.82g$

Molality = $\frac{3.6\times 10^{-4}\times 1000}{17.82g}=0.020$

Thus approximate molality of $CO_2$ in this solution is 0.020 m

5 0

3 years ago

A sample of glucose ( C6H12O6 ) of mass 8.44 grams is dissolved in 2.11 kg water. What is the freezing point of this solution? T

taurus [48]

Answer:

- 0.0413°C ≅ - 0.041°C (nearest thousands).

Explanation:

Adding solute to water causes the depression of the freezing point.

We have the relation:

ΔTf = Kf.m,

Where,

ΔTf is the change in the freezing point.

Kf is the freezing point depression constant (Kf = 1.86 °C/m).

m is the molality of the solution.

Molality is the no. of moles of solute per kg of the solution.

no. of moles of solute (glucose) = mass/molar mass = (8.44 g)/(180.156 g/mol) = 0.04685 mol.

∴ molality (m) = no. of moles of solute/kg of solvent = (0.04685 mol)/(2.11 kg) = 0.0222 m.

∴ ΔTf = Kf.m = (1.86 °C/m)(0.0222 m) = 0.0413°C.

∴ The freezing point of the solution = the freezing point of water - ΔTf = 0.0°C - 0.0413°C = - 0.0413°C ≅ - 0.041°C (nearest thousands).

6 0

3 years ago

If a sample of N2 gas has an initial pressure of 500 Torr and volume of 0.5 L, what will the final volume be if the pressure is

kherson [118]

Answer:

V₂ = 0.4 L

Explanation:

Data:

P₁ (initial pressure) = 500 torr
V₁ (initial volume) = 0.5 L
P₂ (final pressure) = 700 torr

Wanted:

V₂ (final volume)

Equation:

P₁V₁ = P₂V₂ → V₂ = P₁V₁ / P₂

Solution:

V₂ = $\frac{(500 torr)(0.5 L)}{700 torr}$ = 0.3571 L or 0.4 L

8 0

2 years ago

Drag the types of electromagnetic waves to place them in order of increasing wavelength.

patriot [66]

From shortest wavelength to longest wavelength: ultraviolet ,visible light ,infrared

3 0

3 years ago

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