3 years ago

The section of a longitudinal wave in which the particles are densely packed together

Physics

1 answer:

nirvana33 [79]3 years ago

3 0

Answer:

compressions or refractions

Explanation:

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A car is initially moving at 10.5 m/s and accelerates uniformly to reach a speed of 21.7 m/s in 4.34 s. How far did the car move

Zarrin [17]

Answer:

A. 69.9m

Explanation:

Given parameters:

Initial velocity = 10.5m/s

Final velocity = 21.7m/s

Time = 4.34s

Unknown:

Distance traveled = ?

Solution:

Let us first find the acceleration of the car;

Acceleration = $\frac{v - u}{t}$

v is final velocity

u is initial velocity

t is the time

Acceleration = $\frac{21.7 - 10.5}{4.34}$ = 2.58m/s²

Distance traveled;

V² = U² + 2aS

21.7² = 10.5² + 2 x 2.58 x S

360.64 = 2 x 2.58 x S

S = 69.9m

3 0

4 years ago

the net external force on the 24-kg mower is stated to be 51 N. If the force of friction opposing the motion is 24 N, what force

-Dominant- [34]

Answer:

PART A)

External force will be 75 N

PART B)

distance moved will be 1.125 m

Explanation:

PART A)

Given that net force on the mower is

$F_{net} = 51 N$

now we also know that friction force due to ground is given as

$F_f = 24 N$

now we have

$F_{net} = F_{ext} - F_f$

$51 = F_{ext} - 24$

$F_{ext} = 75 N$

so external force will be 75 N

PART B)

deceleration due to friction when external force is removed from it

$a = \frac{F_f}{m}$

$a = \frac{24}{24} = 1 m/s^2$

now we can find the distance by kinematics

$v_f^2 - v_i^2 = 2 a d$

$0 - 1.5^2 = 2(-1)d$

$d = 1.125 m$

so the distance moved will be 1.125 m

6 0

3 years ago

Si el cuerpo no se mueve halle T

Aleks [24]

Well sorry but this is the wrong language.

3 0

3 years ago

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A roller coaster pushes a 25 kg person upward with a force of 300 N. What is the acceleration?

vlada-n [284]

300N/25 kg= divide them for the answer

8 0

3 years ago

which unit of measure would scientist use to measure the thickness of rock layer, created as a result of volcanic activity

frozen [14]

A scientist would use a unit of length appropriate for the magnitude of what he or she is measuring. In this case, since rock is built up very slowly, they would probably use millimetres or centimetres. In some cases they may use meters.

3 0

3 years ago

Read 2 more answers