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Alexus [3.1K]
3 years ago
5

The section of a longitudinal wave in which the particles are densely packed together

Physics
1 answer:
nirvana33 [79]3 years ago
3 0

Answer:

compressions or refractions

Explanation:

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Someone help in physics half life
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To get the number of unstable atoms:
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To get the Number of decayed atoms:
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Follow the pattern for the rest of the table.
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A porcupine eats 3,000 J of plant material. Of this, 2,100 J is indigestible and is eliminated as feces, 800 J are used in cellu
Aloiza [94]

Answer:

3%

Explanation:

The total energy ingested is 3000J and of those 3000J, 100J are used for growth and reproduction, this is the part of production in the porcupine, since the other 800J and 2100J are used for internal processes of the porcupine.

Therefore the production efficiency is 100J of the 3000J, let's find out how much it is in percentage:

\frac{100}{3000}=0.033

⇒0.033=3.3% ≈ 3%

The correct option es 3% of production efficiency.

7 0
3 years ago
What forces come in pairs?
maks197457 [2]

Answer:

Newton's Third Law of Motion

Explanation:

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6 0
3 years ago
Read 2 more answers
The speaker at the concert has the sound intensity level of 100 dB if we listen from the distance 5 m.How far from the speaker d
Mademuasel [1]

Answer:

28.11m far from the speaker the intensity drops to 85 dB.

Explanation:

In the equation for the Decibel scale

  (1). \: \:\beta =10 log(\dfrac{I}{I_0})

The ratio of the intensities can be written as

$ \frac{I}{I_0} = \dfrac{\frac{P}{A} }{\frac{P}{A_0} } $

\dfrac{I}{I_0} = \dfrac{A_0}{A}.

And since

A = 4\pi r^2

and

A_0 = 4 \pi r_0^2,

\dfrac{A_0}{A} = \dfrac{4 \pi r_0^2}{4 \pi r^2}  = \dfrac{r_0^2}{r^2}

meaning

\dfrac{I}{I_0} = \dfrac{r_0^2}{r^2}.

Putting this into equation (1), we get:

\boxed{ (2).\: \: \beta = 10log(\dfrac{r_0^2}{r^2})}

Now, if the intensity is 100 dB when the distance is 5 meters, we have:

100dB=10 log(\dfrac{r_02}{(5m)^2})

10= log(\dfrac{r_0^2}{25})

by taking both sides to the exponent:  

10^{10}= \dfrac{r_0^2}{25}

r^2 = 25 *10^{10}\\r = 5 *10^5

Now equation (2) becomes

\beta = 10log(\dfrac{25*10^{10}}{r^2})

when the intensity level is 85 dB we have

85 = 10log(\dfrac{25*10^{10}}{r^2})

8.5 = log(\dfrac{25*10^{10}}{r^2})

take both sides to exponents and we get:

10^{8.5} =10^{ log(\dfrac{25*10^{10}}{r^2})}

10^{8.5} =\dfrac{25*10^{10}}{r^2}

r^2 = \dfrac{25*10^{10}}{10^{8.5}}

\boxed{r = 28.11m}

Thus, 28.11m far from the speaker the intensity drops to 85 dB.

7 0
3 years ago
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