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Hitman42 [59]
3 years ago
15

Equations can be balanced by using the half-reaction method. Which step should be completed first when using this method?

Chemistry
2 answers:
Tamiku [17]3 years ago
8 0

Answer:

Separate the reaction into half equations

Explanation:

When we want to balance redox equations, we must take cognizance of the fact that a specie was oxidized and another specie was reduced.

Hence we must identify the specie that was oxidized and the one that was reduced and then break up the whole redox reaction into oxidation and reduction half equations.

nikitadnepr [17]3 years ago
4 0

Answer:

D. finding the oxidation states of atoms

Explanation:

i did the review on edge2020

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Which of the following statement is not true?
Helga [31]

Answer: 2

Explanation: Greenhouse gases are very important in keeping our planet just right. If we have too many Greenhouse gases it would be too hot, but we can't eliminate all of them or it will be too cold

8 0
3 years ago
Dissolution of KOH, ΔHsoln:
swat32

Using Hess's law we found:

1) By <em>adding </em>reaction 10.2 with the <em>reverse </em>of reaction 10.1 we get reaction 10.3:

KOH(aq) + HCl(aq)  → H₂O(l) + KCl(aq)   ΔH  (10.3)

2) The ΔHsoln must be subtracted from ΔHneut to get the <em>total </em>change in enthalpy (ΔH).    

The reactions of dissolution (10.1) and neutralization (10.2) are:

KOH(s) → KOH(aq)   ΔHsoln    (10.1)

KOH(s) + HCl(aq) → H₂O(l) + KCl(aq)     ΔHneut     (10.2)

1) According to Hess's law, the total change in enthalpy of a reaction resulting from <u>differents changes</u> in various <em>reactions </em>can be calculated as the <u>sum</u> of all the <em>enthalpies</em> of all those <em>reactions</em>.      

Hence, to get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq)    (10.3)

We need to <em>add </em>reaction 10.2 to the <u>reverse</u> of reaction 10.1

KOH(s) + HCl(aq) + KOH(aq) → H₂O(l) + KCl(aq) + KOH(s)

<u>Canceling</u> the KOH(s) from both sides, we get <em>reaction 10.3</em>:

KOH(aq) + HCl(aq)  → H₂O(l) + KCl(aq)    (10.3)

2) The change in enthalpy for <em>reaction 10.3</em> can be calculated as the sum of the enthalpies ΔHsoln and ΔHneut:

\Delta H = \Delta H_{soln} + \Delta H_{neut}

The enthalpy of <em>reaction 10.1 </em>(ΔHsoln) changed its sign when we reversed reaction 10.1, so:

\Delta H = \Delta H_{neut} - \Delta H_{soln}

Therefore, the ΔHsoln must be <u>subtracted</u> from ΔHneut to get the total change in enthalpy ΔH.

Learn more here:

  • brainly.com/question/2082986?referrer=searchResults
  • brainly.com/question/1657608?referrer=searchResults  

I hope it helps you!

6 0
3 years ago
PLZ HELP!!! WILL GIVE BRAINLIEST!! Balance the following equations to show the law of conservation of mass: (10 points - 1 point
Dafna11 [192]
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4 0
3 years ago
Earth’s inner core:_____ as Earth’s outer core:liquid
KatRina [158]

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Explanation:please give brainliest

5 0
2 years ago
DPLEASE HELP ME TAKE SOO LONG!! (ima fail this test) its a study guide!
8_murik_8 [283]

It’s either b or d, maybe d?

5 0
4 years ago
Read 2 more answers
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